Yemen’s Houthi rebels must allow a UN team to inspect a tanker in the Red Sea, which is loaded with more than a million barrels of oil, the British ambassador to the country said on Monday.
The tanker Safer, which has been kept off Yemen's Red Sea coast to operate as a mini-terminal to store and offload oil from Yemen’s inland fields, has reportedly not been used since March 2015, when the region fell under control of the Houthis.
There are serious concerns that the tanker's structure has deteriorated significantly without regular maintenance and that it could explode.
“They just have to give the UN permission to allow an inspection team to go and make an assessment,” ambassador Michael Aron told The National.
“They will probably conclude that the oil needs to be siphoned off and the tanker then dismantled."
The Houthis agreed last August but then reversed their decision.
“There was a team ready to go in. The UN will not have to put together another team,” Mr Aron said.
The UN has repeatedly warned that the tanker was at risk of exploding, possibly causing a disastrous spill in one of the world’s busiest shipping lanes.
A leak or explosion would affectthe UN said.
The tanker is moored north of Yemen’s main port of Hodeidah, which handles about 70 per cs.
Yemen’s Minister of Information, Muammar Al Eryani, said that a leak from the tanker would lead to 138 million litres of oil being spilt into the Red Sea.
“This would be four times worse than the Exxon Valdez oil disaster in Alaska in 1989,” Mr Al Eryani said.
He said a tanker explosion “would lead to the closure of the Hodeidah port for several months, which would cause shortages in fuel and necessary humanitarian items, in addition to an increase in fuel prices by 800 per cent".
The prices of goods and food would double, Mr Al Eryani said.
He said the explosion would damage Yemen’s revenues from fishing by $60 million (Dh220.3m) a year.


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I did it--I completed all three goals!
I cant wait to hear all about the Women Rock half!
I'm so antsy to hear the recap of the marathon!Ily!Good luck and be safe!
Wow!I won!Thank you so so so much!You rock Katie!
Have fun with your half!
Good luck with the flight and your goal for the half!
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”World Champions” shows the reactions of the Finns to their gold-medal in the World Championships in Ice Hockey in 2011. During one night and the day after it becomes acceptable to be nude in public, and to sing patriotic songs with strangers. Over 100000 people gather at a square in central Helsinki.


The Holy Fathers on mercy
29 July/11 August 2019 year of our Lord
Sermon of His Reverence, Archimandrite Parthenius, on the eighth Sunday after Pentecost, delivered in the monastery Refectory
Today, my dear ones, we’ve heard from the Gospel of this, eighth Sunday after Pentecost, about the miracle that Lord Jesus Christ performed in the desert – namely, He fed overMatthew 14,14-22).
This miracle took place just after Saint John the Baptist’s martyrdom, ordered by king Herod. Christ, mournful, went with His disciples to a lonely place in order to pray. But people, thirsty for His words, eager for His profound teaching, learned where He was and went towards Him in multitudes, walking.
– this is the opening of today’s Gospel reading. Was moved with compassion toward them … When God saw the multitudes arriving there, having left their villages and towns, He was moved with compassion toward them and because of their endeavor, love and their zeal, He healed their diseased. We have seen from the previous Gospel readings that God, in many occasions tests the faith of people before performing a miracle, demanding a confirmation that they believe in His Divine supremacy. In this case however, without being asked for, He Himself healed their diseased and weak. For Him, the fact that they’ve crossed such a long way and came to that lonely place where He was, just to listen to His words, was a sufficient indicator of their faith. Nothing was more important to them, but to delight in the teachings of His Divine mouth. Many of them must have left their families, friends, their work or rest – in a word – left behind every aspect of their everyday life and stayed with God throughout the day till late that night. They were so eager to listen to Christ, that they forgot to take food with them, forgot they’re hungry, forgot about themselves altogether… That’s why, when the disciples realized this, they said to Christ: T
God’s reply is very interesting: They need not depart. Give ye them to eat! Of course, He knew that there wasn’t food enough; but He said so for a few reasons. First, He wanted to test their obedience and faith, to see just how much they trust Him. Also, with this event He taught them to serve people, 1. Peter. 4,10). In the end, He asked them to take care of the hungry people themselves, in order for them to realize their weakness, unless they rely on Him. We have here but five loaves and two fish – the disciples replied. And He said, “Bring them hither to Me” …God, my dear ones, deliberately waited for the evening to come in that desert place, before He performed His miracle. With this He wanted to show us that He is the only way out of any dead – end; that when the Provider is present, there can be no poverty; when the Treasurer is here, even the desert turns into abundance. Remembert, when the Jewish people were leaving Egypt. Namely, as God took pity on His people oppressed by the Pharaoh, He commanded the prophet Moses to carry them out of Egypt, and through him He guided them to the promised land. So, all the people fled and soon came to the Red Sea. Meanwhile, and enraged, pursued them with his army and almost caught up with them. All of a sudden, the children of Israel found themselves in a trap – the sea was in front of them, and the Pharaoh’s army behind their back. They thought: “Did we take the wrong turn? Where should we go now? There is no other way! Why did this happen to us? We didn’t need such a thing! Moses brought us here, it’s his guil4,11). And then, when the people started to disapprove, to reprimand, to cry out to Moses, when they were so afraid and desperate – God performed a miracle. Sometimes, God lets us feel frightened, for us to realize our own weakness, to realize that we can’t be without Him, to humble ourselves and then He intervenes. Because we, as humans, very often put our trust in ourselves and in our own strength; we rely more on our feeble mind and meagerness rather than placing our hopes in Him. Thus, when it seemed like there was no way out, God said to Moses:,15-16). Moses did so and the sea got divided, so the Israeli people passed through as if upon dry ground. The Pharaoh and his chariots followed and pursued them; but, as it is known from the history of the Holy Scripture, the waters returned and all the Pharaoh’s army got drowned. This is asserted by the archeology as well, so whoever wants to know more can do additional reading on this topic.
But what comes to our attention now is the fact that even regarding the miracle with the loaves and two fishes, the situation is equally a dead-end – a desert place, nowhere to buy food from, no way out. From a human point of view, there was really no way out. But, how could The One Who gives food to all this world and Who created the whole Universe, provides for all the live beings; not be able to feed more than five thousand people? What’s that for the Creator of everything?! And, indeed, the Lord performed such a miracle and provided the necessary material food for the people who were primarily hungry for the Word of God, who were longing for the Heavenly Kingdom. The Gospel doesn’t say anywhere that they asked Christ to heal their diseased. No, He Himself showed mercy upon them and first healed their diseased in the end of the day fed them, too. What else does this miracle tell us? Before performing it, God looked up to Heaven, indicating that all the food, even the carnal one, comes from above, from God. That’s why He wants us to be grateful for everything He gives us. Saint John the Chrysostom says: He who always begins his meal with a prayer and thanksgiving to God and finishes it in the same manner, his table will never be empty”. We have somehow forgotten to be grateful to God for the gifts He provides us with. Often, we preoccupy too much with overloading our homes with food and all the other material wealth; with making provisions for a safe future. Or, we have this bad habit of saving money throughout the year so that we could go somewhere on a vacation and there indulge into abundant food and drinks, allow ourselves every luxury, without even noticing around us those who are in need of food or clothes.
In this regard, the miracle also brings us to the conclusion that God wants us is to be plain, modest, be content with what we have. He fed the people with the things available at the moment. The apostles had five loaves and two fish – the simplest food at that time. Fish could be found nearby; they were fishing it at the lake and used it for food. And the loaf is a synonym for a basic meal. Thus we say in the “Lord’s prayer”: “Give us this day our daily bread”. We ask for the simplest thing. The Lord teaches us to be plain everywhere, in each place, to be economical. The Gospel shows us that after everyone was fed, apostles didn’t throw the remaining food although it was so easily obtained, it was God’s gift; but rather collected all the remains in twelve baskets. Hence, we should not throw food but be grateful to God instead and save up. I remember when I was young, as a child, if we accidently drop the slice of bread we held on our hands, my grandmother would pick it up and say: “Now, kiss it!”. So, we would kiss the bread and say: “Lord, forgive us for treating the bread without due respect”. That’s how they taught us to be modest and thankful, to respect every gift from God. Can you see that somewhere nowadays? We came to the point where enormous amount of food is thrown away, while many people are starving to death…
Let’s get back to the evangelic story. Both events – breaking of the loaves in a desert place and crossing the Red Sea, I would say, are hopeless situations – yet God performed a miracle, offered a solution, a way out. So, when we are with Christ, there is no hopeless situation. That’s why one should never be desperate. Seek from God. Seek first the Kingdom of God, wish eagerly to be with Him, tell Him you love Him. These people from today’s Gospel went to seek God in the desert place. They had hope, and most important – they Loved Christ; in order to seek Him, you should love Him. That’s exactly what prayer is: love and longing for God. To pray to God means to love and to seek Him. I go to a monastery because I love Him and I seek Him. Look how many people came to the monastery today, came from all around the country. They drove miles to come here. That’s why God helps them constantly. Many of those who come here often are aware that God rewards them for their feat, receives their prayers and helps them according to their faith. And the faithful, on their part, help us. Thus, we have never been left without bread. There’s always food on the table. I remember, a year before I started my monastic feat at the Bigorski monastery, I came here for the feast of Saint John the Baptist. There I entered a conversation with some people preset, among which with our respected Metropolitan Timothy too, as to how beautiful the monastery was and yet so sad there were no monks in it. We concluded with regret that there were no conditions for monasticism: no Orthodox population around, the monastery couldn’t have its own economy, so consequently it would be hard to endure. But, behold, by God’s mercy and blessing, not only our brotherhood – there’s thirty of us, but so many other people have been fed here, many diseased were healed. What’s all that? That’s what God said to the Apostles: Give ye them to eat! He gave to the Apostles; and they distributed to the people. And it has always been so: today God gives to his servants, the Archbishops, clergy, monks; and they convey to the faithful. Behold, monks went to a desert place; they left everything of this world behind and went to seek God. And we have already said that where He is, there you will find spiritual abundance. That’s why people come to monasteries, to drink from His spring. Of course, God is everywhere and fills everything, He is present in the cities as well, in the homes, in people; and anyone who seeks Him, will find Him. Yet, in the monasteries, in the cenobitic monastic communions, His mercy abundantly flows and nourishes everybody.
In the end, I would like to appeal to you again: be always thankful to God and believe, He will never leave us empty. The table of the grateful man is always rich. I’ve seen it many times in my life. Place hope in God and don’t say: “This is impossible, I’m in a dead – end, it’s hopeless”. That’s what the Israeli people said standing before the Red Sea, and the disciples who were aware that there was not enough food to feed the multitudes. But God took care of both. For Him everything is possible – what we need is just to love Him and to seek Him.
May God give us love and a zeal to constantly seek Him, just as these people from today’s reading sought Him in the desert and were fed both spiritually and materially and were healed from diseases!
May you all be safe and sound and in love with God!
The five loaves and two fish
Believe ye that I am able to do this?Thoughts on Living with Cancer – Part 1
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Three games were nominated for the 2019 Kinderspiel des Jahres – Valley of the Vikings, Fabulantica, and Go Gecko Go! – but Valley of the Vikings took home the prize. "tactical game of skill"Spiel des Jahres 2019 Nominees Announced
The nominees for each respective category (along with their designer(s)) are:
LAMA (Reiner Knizia)
(Children's Game of the Year):
Go Gecko Go! (Jurgen Adams)
Wingspan (Elizabeth Hargrave)
Back in May we announced the nominees for the renowned Spiel (Game of Year), Kennerspiel (Connoisseur-Enthusiast Game of the Year), andawards. The winners have been announced. This year/Next Move games won the Spiel des Jahres.
And, finally, Funkelschatz won the Kinderspiel des Jahres. Also known as Dragon's Breath and published in the USA by HABA, Funkelschatz is designed by Lena and Günter Burkhardt.
Dragon's Breath from HABA wins the Kinderspiel des Jahres award for 2018
Dragon's Breath is a cute little game for ages 5 and up, and in it you will have four young dragons and one dragon dad, trying That ice column in the game is represented by a stack of rings filled with plastic gems. Each round the young dragons will pick a gem color that they think will come out of the ice when the dad melts it.  There is also some holes in the board that if a gem n'''s BrThe Spiel des Jahres award nominees have been announced for 2018 across their three categories; Spiel desh Jahres (Game of the Year), Ki. The nominees are:
Funkelschatz (Dragon's Breath)
The winners of the Spiel des Jahres and the Kinnerspiel des Jahres have yet to be picked, but they have chosen the Kinderspiel des Jahres winner. And the winner is Ice Cool.
Ice Cool is definitely worthy of this title as it is a very fun dexterity game that works for adults and kids alike. In the game you have one person being the hall monitor, trying to keep everyone in class, and everyone else are students trying to sneak away for a snack. You will be flicking your weeble-wooble like penguin around the board trying to go through the doors with your color fish on them. The more fish you collect the more points you get, and for the hall monitor, the more students you catch and take their ID from, the more points you get. After everyone either gets their fish or the hall monitor catches everyone, the player being the hall monitor switches and you play another round. Once everyone has been the hall monitor once you count up points, and the most points is the winner.
Kingdomino by Bruno Cathala
Prestigious tile laying for 2 to 4 crowned terrain planners
Publisher: Sit Down !, Distribution: Pegasus Spiele
Cooperative shopping house break for 1 to 8 hectic heroes
ICECOOL by Brian Gomez
Publishing house: Amigo Interlaced snips for 2 to 4 ice-cold schoolchildren from 6 years
The Mysterious Forest of Carlo A. Rossi
Publisher: Iello, Vertrieb. Yikes! & Friends
Adventurous journey for 2 to 4 clever scouts from 6 years
Connoisseur-Enthusiast Game of the Year 2017 (Kennerspiel des Jahres)
Planetary project development for 1 to 5 climate changing corporate boards
Kinderspiel des Jahres Winner Announced
Krazy WORDZ
Isle of Skye: From Chieftain to King, by Andreas Pelikan, Alexander Pfister and Lookout Games
T.I.M.E Stories, by Manuel Rozoy and Space Cowboys
Tm! which is a great little cooperative game well suited for introducing a child to the cooperative genre.
Die geheimnisvolle Drachenhöhle (a.k.a. The Mysterious Dragon Cave)
Dschungelbande
Mein Schatz
In addition to the Spiel des Jahres two other awards are given out. They are thefor best heavier game and the Kinderspiel des Jahres for best children's game. This year's winners are Broom Service and published by alea for the Kennerspiel des Jahres and Spinderella designed by Roberto Fraga and published by Zoch for the Kinderspiel des Jahres.t for a board game and is quite often accompanied by a large increase of sales. Cas well as the nominees that didn't win. For the full list of nominees and recommended games you can visit the official site for each award:


Employers have the option of offering quality coverage as employer-paid or voluntary (employee-paid) benefits: Aprovide taxmeans for a business to reward key employees is to have the businessfor them. The term Executive Carve Out refers to a select "class" of employees who are eligible for these LTCI policies.
The business may be able to deduct the cost of the premiums using pretax dollars, just like health insurance.
The total premium paid by the business iunless the executive has an ownership interest in a pass-through business entity like a partnership, S corporation, LLC, etc.).
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Subject to the type of business, (e.g., C Corp, LLC, Professional Corp., sole proprietors or partnerships) various deductible scenarios exist pertaining to owners and premiums paid on their behalf.
Long-term care insurance is becoming an essential part of today's benefit packages, whether a voluntary benefit that employees pay for, a partially-paid or executive carve-out plan paid for by the employer.


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Sign and Magnitude Example 2 : Represent 25 in sign and magnitude. +25 sign magnitude 0 <PHONE> 25 in sign & magnitude value is 011001 Ones Complements and Twos Complements. Ones Complements. Ones complements is used in binary number. The ones complement of a binary number is obtained by changing each 0 to 1 and 1 to a 0. Only change ...
In the sign-magnitude method, the magnitude bits represent the true binary value and the bit preceding the MSB represents the sign of the following bits. C) In the signed-magnitude system all numbers, regardless of their sign, are in straight binary format preceded by a "0" or "1" to denote the sign.
Signed Magnitude Representation uses the Most Significant Bit (MSB) as the sign bit. The MSB is the leftmost bit in a binary number, so in the binary number 101101, 1 is the MSB. In Signed Magnitude Representation, the sign of the number is interpreted as follows: 0 means Positive. 1 means Negative. The magnitude is the size of the number ...
07 4-bit Signed Binary Number Comparison. 08 Rust signed two’s complement integer types. ... Signed Magnitude Signed Ones' Complement Signed Two's Complement +7 ...
This lectures talks about Signed Binary Numbers including signed magnitude convention and signed complement system. Also teaches how to convert 2's complemen...
The sign-magnitude representation of a binary number is a simple method to use and understand for representing signed binary numbers, as we use this system all the time with normal decimal (base 10) numbers in mathematics. 1 Signed Magnitude • In an 8-bit word, signed magnitude representation places the absolute value of the number in the 7 ...
SiMaN: Sign-to-Magnitude Network Binarization Mingbao Lin 1Rongrong Ji1 2 Zihan Xu Baochang Zhang3 Fei Chao1 Mingliang Xu4 Chia-Wen Lin5 Ling Shao6 Abstract Binary neural networks (BNNs) have attracted broad research interest due to their efﬁcient stor-age and computational ability. Nevertheless, a signiﬁcant challenge of BNNs lies in handling
Oct 01, 2016 · A 2009 paper in the Publications of the Astronomical Society of Japan noted that the rate of orbital decay of binaries is “1–2 orders of magnitude faster” than theory predicts. Although our estimate is 2–3 orders of magnitude faster (that’s around 400 times faster), the paper confirms our basic findings.
See full list on andybargh.com
The rest of the question presents an interesting procedure for adding binary representations of integers. Instead of using two's-complement exclusively, however, this method begins with the two operands ($-5$ and $3$) in a four-bit signed-magnitude representation, and ends with the result ($-2$) in four-bit signed-magnitude representation.
Chapter 4: Binary Operations and Relations 4.1: Binary Operations DEFINITION 1. A binary operation on a nonempty set Ais a function from A Ato A. Addition, subtraction, multiplication are binary operations on Z. Addition is a binary operation on Q because Division is NOT a binary operation on Z because Division is a binary operation on
Sign Magnitude Format. The first format for negative numbers we will explore is the sign-magnitude format. The format is easy to understand. For any given binary number add an additional bit to represent the sign of the number. If the sign bit is set, then the number is negative. If the sign bit is clear then the number is positive.
The remaining 7 bits will be used to represent the magnitude. The binary representation of decimal 31 is given by the following sequence 0011111. That is, 31 10 = <DIGITS>. The sign-and-magnitude representation of the number is <DIGITS>. To represent the sign-and-magnitude of – 31, the sign bit is changed from 0 to 1.
Negative Binary Numbers Sign-magnitude The leftmost bit determines the sign of the quantity it's representing "1" means negative "0" means positive For more info and practice for Sign-Magnitude, visit: Sign-Magnitude One's Complement Write the positive value of the number in Binary Reverse each bit of the number from 1 to 0 or 0 to 1
Not only is the average time an order of magnitude faster than the already fast binary search Python implementation, but the speed is also sustained across all elements regardless of where they are. The price for that gain is approximately 0.5 GB of more memory consumed by the Python process, slower load time, and the need to keep that ...
Which is the most significant bit in signed magnitude How to convert from signed binary to decimal What drawbacks are associated with the signed bit representation; Practice Exams.
Signed-Magnitude representation: • This is the simplest method. • Write the magnitude of the number in binary. Then add a 1 to the front of it if the number is negative and a 0 if it is positive. • Examples: +7 would be 111 and then a 0 in front so <DIGITS> for an 8-bit representation.
Now, if we take two’s complement of unsigned binary number then we get signed binary representation of a number which is nothing but negative equivalent the unsigned binary number. To understand this in an easy way, consider previous example of 38 10. Let us convert the number 38 10 into binary. 38 10 = <DIGITS>
Jan 11, 2020 · Sign-Magnitude Form. If we have an n-bit binary number, one of the bits is the sign bit. The remaining (n-1) bits in the binary number represent the magnitude. This sign bit represents whether the binary number is positive or negative. The binary number system has only two values – 0 and 1.
For the case of binary coupled data, however, only methods exist that go for a simultaneous analysis of all data blocks but that do not account for noise heterogeneity. Therefore, in this paper, the SIMCLAS model, being a Hierarchical Classes model for the simultaneous analysis of coupled binary two-way matrices, is presented.
Conversion of Signed Numbers to Two’s Complement. Signed Numbers are 8 bit quantities with the least significant 7 bits representing the magnitude and the most significant bit indicating the sign. 0 in this bit indicates the number is positive, and 1 indicates it is negative. There is no magnitude information in this 8 th bit-just the sign.
Converting a 2's complement code c to a signed value If the encoding c begins with 0, it encodes a positive value and the value is "face value" in binary
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Binary to hex or octal conversion 25 Group binary digits into groups of four/three digit. • Binary-to-hexa decimal: <PHONE> 6 B 7 • Binary-to-octal: <PHONE> <DIGITS> • Hexadecimal-to-binary: A 1 <PHONE> • Octal-to-binary: 5 0 3 <PHONE> 001
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Sep 02, 2020 · Figure 3. Left: posterior distribution for the individual spins of GW190521 according to the NRSur7dq4 waveform model. The radial coordinate in the plot denotes the dimensionless spin magnitude, while the angle denotes the spin tilt, defined as the angle between the spin and the orbital angular momentum of the binary at reference frequency of 11 Hz.
Mar 22, 2017 · The magnitude scale is much like golf in that the lower number means a greater brightness on the magnitude scale and a better score in golf. Loosely speaking, the 21 stars that are brighter than ...
Feb 15, 2009 · That is how binary numbers are represented to be positive or negative using sign and magnitude notation (first number is the sign and the rest are the magnitude, or value). My question is asking how this is done using hexadecimal numbers where instead of 0-9 or 0,1 the base numbers are 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F. Values 0 through 15.
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Jul 14, 2019 · This discussion on In signed-magnitude binary division, if the dividend is (11100)2 and divisor is (10011)2 then the result is _____a)(00100)2b)(10100)2c)(11001)2d)(01100)2Correct answer is option 'B'. Can you explain this answer? is done on EduRev Study Group by Computer Science Engineering (CSE) Students.
The integer binary signed number is represented as follows: o For a positive integer binary number, the sign bit is 0 and the magnitude is a positive binary number. o For a negative integer binary number, the sign bit is 1. The magnitude is represented in any one of the three ways:-
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This video explains the binary addition of unsigned and signed numbers, which are used in digital logic design. Two's complement form and its addition & subt...
(8)Represent the following decimal numbers in both binary sign/magnitude and twos complement using 16bits: +512; -29 (4)Represent the following twos complement values in decimal: 1101011; <DIGITS> (8)Assume numbers are represented in 8-bit twos complement representation. Show the calculation of the following: 6 + 13-6 + 13; 6 - 13-6 - 13
Subtraction and Borrow, these two words will be used very frequently for the binary subtraction. There are four rules of binary subtraction. In binary subtraction. 0-0 = 0 1-0 = 1 0-1 = 1 (1 borrows out) 1-1 = 0. Example of Binary Subtraction: Take two numbers, suppose numbers are 20 and 10 their binaries 10100 and 1010. Now sub 10 from 20. 20 ...
Signed magnitude is a convention in which we express a decimal number as a positive or negative binary number using its most significant bit. The most significant bit is the left-most bit which...
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Generally, binary options pay out within a range of 75% to 95%. This percentage is made clear before the trade is made. Other than being higher or lower than the starting price, the closing price does not affect the magnitude of the payout. As binary trading becomes more sophisticated, the amount that can be won is evolving too.
· Sign-and-magnitude representation is the conventional way for representing signed integer numbers · The number is represented as a sign followed by a magnitude (e.g. +50, -40) · A number that contains no sign is considered positive
3.1 Signed Magnitude of Binary Numbers. In a sign magnitude representation, the most significant digit (bit) is 0 for positive binary numbers and 1 for negative binary numbers. As we know, for large binary numbers it is more convenient to use hexadecimal numbers. In most computers, negative binary numbers are stored in twos-complement form.
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Signed Binary Numbers : 15 Signed Binary Numbers Example: 5-bit numbers 01011 (unsigned binary) 01011 (signed binary) 11011 (unsigned binary) 11011 (signed binary) This method is called “signed-magnitude” and is rarely used in digital systems (if at all) In computers, a negative number is represented by the complement of its absolute value ...
sign and magnitude code 正负及大小码 sign&magnitude 原码 sign magnitude arithmetic 符号数值运算 sign magnitude code 符号 sign magnitude representation 符号数值表示法 sign-and-magnitude 原码 ; 表示法 Sign for angle metric magnitude 现今所采用的角度符号 sign-and-magnitude notation 符号数值表示法
The binary number <DIGITS> converts to 123 in Decimal and 7B in hex.
Yet Another Sign-Magnitude Example 0 0010 (+2 10) + 1 0101 (-5 10) Signs are different - determine which is larger magnitude Put larger magnitude number on top Subtract Result has sign of larger magnitude number… 1 0101 (-5 10) - 0 0010 (+2 10) 1 0011
What is the 32-bit sign-magnitude binary integer representation for the decimal integer -47? SOLUTION. 1. S = 1, for negative number. 2. Solve as for an unsigned integer for the remaining 31 bits. 47 10 = <DIGITS>. Organize the bits, padding with zeroes between the sign and the magnitude: <DIGITS>. Convert to hex:
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Get code examples like "converting decimals into binary" instantly right from your google search results with the Grepper Chrome Extension.
Probably the most straightforward one is the sign-magnitude, which builds naturally on top of unsigned integers. When a binary sequence is interpreted as sign-magnitude, the most significant bit plays the role of a sign bit, while the rest of the bits work the same as usual: In binary, use either 7 bits or 8 bits (by adding a leading zero) to represent an ASCII character. In octal , it is represented with 3 characters (from 000 to 177). In decimal, the number is between 1 and 128 (from 1 to 3 characters).


iimoteZ`` dataset.
model = kNNClassifier(**best_param,mac_metric="dtw",
print("Time: ", round(elapsed, 2))
# We achieve an accuracy of 70% by full k-NN-DTW model. The model takes 12.75 $s$ to complete the task.
# ## Using MAC/FAC Strategy
# Here we would look into speeding up the classification of the kNNClassifer model by using the MAC/FAC strategy.
# The classification would happen in two stages:
# - MAC stage: The model retrieves a candidate subset of size ``mac_neighbors`` using the ``mac_metric``.
# - FAC stage: The model retrieves the closest ``n_neighbors`` from the candidates set using ``DTW``, and consider them for prediction/classification.
    "mac_neighbors": np.arange(20,40,5)
#We use the the same metric_params as supplied to previous model, for fair analysis.
model = kNNClassifier(mac_metric="euclidean",
gscv_mf
best_param_mf = gscv_mf.best_params_
print("Best Parameters: ", best_param_mf)
print("Best Accuracy: ", best_score_mf)
model_mf = kNNClassifier(**best_param_mf,mac_metric="euclidean",
print("Retrieval Time: ", round(elapsed_mf, 2))
# kNNClassifer w/ MAC/FAC strategy achieves the **same classification accuracy** of full-kNN-DTW. However, the model is **10 times faster** than the previous one.
models = ["Vanilla", "MAC/FAC"]
         mew=2,
fig.legend(loc=(0.65,0.75))
ax.set_ylabel('Accuracy (%)')
# ## This is the 2-layer neural network notebook for ECE C147/C247 Homework #3
# Please follow the notebook linearly to implement a two layer neural network.
# Please print out the notebook entirely when completed.
# The goal of this notebook is to give you experience with training a two layer neural network.
# Before loading CIFAR-10, there will be a toy example to test your implementation of the forward and backward pass
from nndl.neural_net import TwoLayerNet
# Note that we set the random seed for repeatable experiments.
# ### Compute forward pass scores
##
scores = net.loss(X)
    [-0.38172726,  0.10835902, -0.17328274],
print(np.sum(np.abs(scores - correct_


Ts' W
From this Spanish period, the Ranchos began trading hides with US merchants in Boston for goods from New England, sailing around South America. The Ranchos also traded with English and European merchants. This trade continued through the Mexican period (1823–1848) as immigrants were offered land if they converted to the Catholic religion and became Mexican citizens, which many did. Many Anglo immigrants married into Spanish families, becoming Californios inheriting and acquiring lands and ranchoswnership of California in 1821, it was soon evident that the era of mission-domination of virtually all land was over. Although the Yorbas-Peraltas retained the 65,512 acres they had been granted by the Spanish, adjacent land became available. By 1837, 35-year-old Jose Sepulvada was awarded an enormous tract and five years later was again awarded land. Combined, his ownership extended almost 47,000 acres, including north to the Santa Ana Mountains, east to today's 55 Freeway, and south to Laguna Beach. It was later discovered that this grant did not include the land surrounding Newport Bay and the oceanfront at Newport Beach, for each was considered worthless.<ref>Baker, Gayle Newport Beach", HarborTown Histories Publications, Santa Barbara, CA, 2004, ISBN (print) 0-9710984-3-3 (e-book) 978-0-09879038-3-9, p. 8-9</ref>
Establishment of Newport
James IrvineIn 1846, at the age of 19, he joined the parade crossing the Atlantic, bound for New York. He continued his journey west, becoming a miner and a merchant. He was soon prosperous enough to partner with the Flints and Bixby to establish a wool business. When they had amassed enough money, they bought Sepulveda's rancho. They were also ready with cash when the Yorbas'- Peraltas' rancho was dissolved by court order. Soon, they were the largest landholders in the region, dominating over 100,000 acres. Tirelessly focused on ranching, Irvine and his descendants continued to own enormous tracts of land, their Irvine Ranch intricately intertwined with the evolution of Newport Beach.
James McFadden, one of 11 children of Scottish ranchers, journeyed to California in 1868 and immediately saw the potential of the Newport area. Soon joined by his brother, Robert, they began buying as much as possible and subdividing it immediately, seeking buyers. After the Civil War, the parade of settlers significantly increased. While most sought prime agricultural land, some did gravitate to the Newport area and a small settlement was born.
During its early years, Newport had many names, including Bolsa de Gengara and Bolsa de San Joaquin. When settlers began to arrive, an easier to pronounce, more prestigious name was wanted. Although there is no proof of its source, most believe that the Name "Newport" came from one of two sources:
1) Some credit Dunnels, who exuberantly proclaimed he had found a "new port" when he crossed the bar.
2) Others contend that an employee of the Irvine Ranch suggested it at a meeting concerning commerce on the bay.
In 1888, the McFaddens decidedif they moved it from the inner shores of the bay to the oceanfront, where it was connected by rail to Santa Ana.  So they built McFaddens' Wharf at the location where the Newport Pier is today.  "McFadden Wharf soon became the largest business in newly created Orange County", California.  It lasted for a's major seaport. The McFadden Wharf and railroad were
In 1905, the Pacific Electric "Red Cars" day.
In 1908 and 1909, with permission of the Orange County Board of Supervisors, William Collins moved his small dredge to the eastern part of the Newport bay, a mud flat called "Snipe Island",y across from the Pavilion, piling the sand and silt up on the mud flat and thus Balboa Island was born. Balboa Island was a summer vacation place. Most homes had no heaters, and were closed up in the winter. Families came down for the entire summer. Cooking was done on a gasoline stove as there was no gas or electricity. Coal oil lanterns and candles were used.
In 1912, the seawall was partially replaced by a cement barrier (cheap German cement). Beek got the first contract for a ferry between the island and Balboa Peninsula.
In5-year franchise, using the ferry boat Joker'', which
In 1936, Newport Harbor was officially dedicated.  This occurred after a $1.8 million project dredged out the sandbars and extended the jetties.
Later in the 20th cs "the Duke". Orange County later named its airport for Wayne. Other.  F Other notables included television star Bn's most frequent guest host, Joey Bishop.spent many summers living at the Balboa Bay Club.
In 1953, the third international jamboree of the Boy Scouts of America held its event where Newport Center and Fashion Island now sit. It was the first jamboree held west of the Mississippi River and had 50,000 scouts from all 48 states, Alaska, Hawaii and 16 foreign countries. Thousands of tents were pitched in the area reachable only by a two-lane muddy trail called Palisades RoadScouts.
In 1963, the first phase of Eastbluff, the first "community" to be developed under the Irvine Company's master plan, was opened.
In 1967, Fashion Island was completed.  Newport Center Drive, a circular road, embraces Fashion Island and gives it the "island" name. Newport Center's first office building, at 400 Newport Center Drive, was completed the same year.


People often ask us: What is the best electric bike for me? Well, that depends on what you mainly want the bike for. Many people just want an electric bicycle for short trips - to visit the local shop, to drop by friends, to go to the park, or for light recreation. Bicycles can be a lot faster than walking, and a lot more convenient (and cheaper).
Unfortunately, around 86% of the population find that storing their bike is awkward and the majority of these people say it stops them using their bike. So, if your intention is to use your e-bike for short trips, it is important that it is convenient.
Where do you keep your bike at home?


blessings can come in various ways, spiritual ones is the best, for money can not buy what we get from the Spirit of GOD as we grow in HIS Grace and Knowledge. The WORD of GOD is to be the daily BREAD and it is FREE in most places. The Spirit of GOD is the REFRESHING WATER of LIFE that will never run dry for the thirsty, and they both will sustain you. JESUS paid the price for us to eat and drink FREELY! These ministries do cost. Abraham gave a tenth of his earnings, and the full pay check you make is GOD’S blessing anyhow, and the tenth belongs to the Kingdom’s work. I do wonder how much money is spent on pleasure, unnecessary cloths, food, drinks, driving around using gas, wants…..add up in a week what each one of us spends each dollar on, and figure out at the end of the week how much we spent on eating out, a pop, a candy bar, buying a item we did not have to have to survive on….Is it more than the ten percent that belongs to the work of GOD?
Hmmmm, I feel grieved in my spirit. I agree with you Gil. While Nancy may feel you can just toss $199 away, I don’t believe that is what you are doing or saying. I cannot afford to purchase the CD’s either, however, if I had the money: I would purchase them. 1. I would be able to watch them repeatedly until I get to know the word this minister is teaching. 2. I can learn enough about it and keep it in my memory to be able to witness this word to others. 3. I can pass the CD’s on to others so they may be able to gain the same understanding. 4. How old is this minister and how much longer will he be ministering. I could keep his words after he passes and it will keep the memory of his teachings in my memory. 5. I have ten extremely pesty 20 year olds who are bombarding me with questions about this and they are looking at the power people claim to have. The power the witches use in Wicca, Transcendentalism powers to move your spirit to another area of the world, etc. The power of the Holy Spirit and what it is. I could use these CD’s to help them get to know Jesus while teaching them how not to be deceived by all of that garbage. Then they in turn, can share that information with others they know who are asking too. They are called souls. Yes, they can get on here and get some of the information free like I do. But, as I have said, a CD ensures this ministry will remain alive and well. The costs of the CD’s are cheap compared to the value of a soul. Those of us who minister for the Lord need any helpful tools we can receive. This money is not to make this man wealthy, it is to pay for expenses. Who out there has children in school? Are you buying or renting books to teach your kids? What is the difference? That you don’t have to buy the CD’s and you do have to get the school books? We are purchasing those books so our kids can learn. We purchase our Bibles so we can learn. Is that Bible free? Only if someone gives it to you as a gift. Gil stated Irvin Baxter has been studying this for years. I have only been on this for one month. Without his word, I would be stuck by now. He is making the information he has so much easier for me to study and in a lot less time. Who has the time he has put into this? Everyone works. Irvin Baxter would have to be a billionaire to be able to pass all of this on to us for free? I just don’t see it. I’m not a billionaire, neither is he? He is doing as God has asked him to do. Those of us who have the money should be obedient to God to help increase the ministry. A world ministry is not cheap and this ministry is covering the world, not just one house hold or one church. I dearly, dearly appreciate the free information, I really do. But if I had the money, I would purchase the information to keep. I love the Lord and I love him so much, that I would give all I have to be able to have information about him. I do not believe there is a price you can put on his word. It is far too valuable and precious to me.
Irvin Baxter conferences are free to the public. Irvin and his wife Judy pastor since he was 18 years old after his father who was the pastor passed away, and he and Judy to my knowledge lived up stairs from their Church, even after it grew big enough for him to live in a fine home. Irvin and his wife have given their daily life unto the anointed talent and call that GOD had called them unto. What drives Irvin, you & I to not be deceived, but to be saved for eternity. The cost of the material is what he needs to reach out. Irvin is just another willing vessel living his life for the gospel to reach as many as GOD will allow him to reach. Irvin does not live the rich and famous life at all. He has poured everything into reaching the world with the gospel of the Kingdom.
While this may all be in the Word, or just a fact of life, Christ also said “we have always the poor with us”. So, everyone can’t afford to pay for this – and it’s not wrong for them to admit it. I can’t afford it, and there’s nothing wrong with me, my faith, my needing to pay my living expenses, etc., first, after paying my tithe and giving whatever I am able to give, and plant in good soil. Those of us who don’t have $199 to put towards a deeper understanding of the end times are obliged to find what we can learn in other ways – but how about considering this – while you may be able to just toss $199 to something which makes it easy to learn about Bible prophecy – which is all neatly organized and explained – those of us who are not able to pay for it actually put forth more effort – like Ruth gleaning “leftovers” in Boaz’ field – and so we “pay” a higher price in physical and mental effort to learn what you are able to be spoon fed. God bless you, and may– I am concerned that it may be a difficult thing for you to live that way.
No. Jesus never charged money. Walking with him was free. You miss it completely! You cannot justify what(man) has done to steal what is free and should always be given freely. That is what makes a disciple! To give and not ask for anything in return, trusting that God will provide. That is what (giving) is all about. People tithe from their heart to support the missions. Even that has been twisted in the churches to support the buildings instead of the journey!
Agree Renee, Jesus is the perfect example of HIS day, and we are to walk like HE did. I feel a day will come, that we will see the difference between those who are true disciples and those who are making it a living for riches of this old world. The buildings are getting more elaborate and very costly while the mission fields are needy. Two wrongs do not make a right. There is a right way with pure ministries. The days of those called that went out in pure faith and no money, but a call from JESUS and a Burden for souls to be reached are not over. JESUS said, HE would not come back until HIS Gospel is preached in all the world until all nations, then the end will come. I am sure JESUS knew that the media airwaves, planes, boats, automobiles would be a way of the gospel reaching the world…and it takes funds to get the message there. JESUS also knew that there would be abuse, and HE will judge it as well.
Brother I understand what you mean. I have just started back seeking the Lord and let me tell you he will not leave you ignorant. Just keep seeking him. Those who charge money for the gospel will pay for it in the end. I started reading in the book of James and ended in Jude. It talks about how they will make merchandise of you. I believe that it will be as it was in the days of Acts home to home groups of brothers and sisters in Christ sharing as each one was blessed and given. Pray that God would put you in touch with who you need to be speaking with so that you may grow. Most people think we will be taken up before Christ returns but I believe that we may have to die for our faith. May the Lord Bless and Keep you He will give you His Holy Spirit that you will not lack anything you need to keep your self.
GOD is the GOD of the whole world. There are Christians in areas of the world that do not have funds, but they have Faith and are


Welcome to the Perl review for Week 106 of the Weekly Challenge! Here we will take the time to discuss the submissions offered by the team, factor out the common methodologies that came up in those solutions, and highlight some of the unique approaches and unusual code created.
Abigail, Adam Russell, Athanasius, Cheok-Yin Fung, Colin Crain, Cristina Heredia, Dave Jacoby, E. Choroba, Flavio Poletti, James Smith, Jorg Sommrey, Lance Wicks, Laurent Rosenfeld, Lubos Kolouch, Mohammad S Anwar, Niels van Dijke, Paulo Custodio, Pete Houston, Peter Mayr, Roger Bell_West, Simon Green, Stuart Little, Ulrich Rieke, W. Luis Mochan, and Wanderdoc
There were 25 submissions for the first task this past week. The task involves comparing each element to its neighbors; these comparisons can be broken down into two groups — those that directly examine the elements themselves, and those that indirectly reference the values through the index positions of the array holding them.
And yes, there were also a few methods that defied this simple categorization.
The methods on the whole were short and succinct. Let’s have a look at some of the techniques we saw.
ITERATING over the INDICES
When comparing neighboring elements in an array, it’s natural to consider them by index. That way, the adjacent element is either one index higher or lower, and its position can easily be computed mathematically.
…using either a for loop
Athanasius, Cheok-Yin Fung, Cristina Heredia, Dave Jacoby, E. Choroba, Lance Wicks, Laurent Rosenfeld, Paulo Custodio, Pete Houston, and Roger Bell_West
The for loop seemed to be the go-to tool when iterating through the array values. First the array is sorted — every submission required this basic first step. A range is then constructed over a subset of the indices, either starting at 1 or ending 1 before the last index. Then two neighboring elements can be accessed at the index and either minus or plus one, respectively. The range is traversed, and the difference found between each pair. If this exceeds the current maximum known gap it takes the place of the old value.
To start us off Lance brings us his own Maxgap module, because that’s how he rolls.
Inside is a very clean implementation of the technique: first sorting, then iterating over a numerical list of the the indices, choosing the largest difference between the value at an index and the value at the index previous. It’s clean. I like it.
sub maxgap {
my ($self, @integers) = @_;
@integers = sort @integers;
my $maxgap = 0;
for my $i (1 .. @integers-1){
my $gap = $integers[$i] - $integers[$i-1];
if ( $gap > $maxgap) {
$maxgap = $gap;
return $maxgap;
Choroba brings us a quite compact example of a very similar implementation. You might consider this to be a basic form, with the three steps laid out: sort, iterate and compute the differences, and from these locate the maximum value.
sub maximum_gap {
my @arr = sort { $a <=> $b } @_;
for my $i (1 .. $#arr) {
my $diff = $arr[$i] - $arr[ $i - 1 ];
$max = $diff if $diff > $max;
Christina builds a loop that stops one before the last element, comparing a given index with the one following. Before or after makes no difference.
if (@N != 1) {
my @sorted = sort { $a <=> $b } @N;
for (my $i= 0; $i<@N-1; $i++) {
$sub = $sorted[$i+1] - $sorted[$i];
if ($sub > $result) {
As usual, the monk provides us with a robust application to the task, with thorough input validation and well-structured output. They also thought to include a --unique flag, that when set on the command line preprocesses the elements for uniqueness; as the gap between any element and itself will always be 0, any duplicates can be safely removed without harm. The only penalty is the time it takes to do so, so the feature is left as an option.
my ($unique, $N) = parse_command_line();
printf "Input:  \@N = (%s)\n", join ', ', @$N;
my @sorted  = sort { $a <=> $b } @$N;              # Sort ascending
@sorted  = uniqint @sorted if $unique;          # Optionally remove dups
my $max_gap = 0;
# Test every difference between successive elements in the sorted array
for my $i
my $diff = $sorted[ $i ] - $sorted[ $i - 1 ];
$max_gap = $diff if $diff > $max_gap;
print "Output: $max_gap\n";
There’s always going to be that sort of person who says: “You know you could save half on that refrigerator if you just built it yourself.” I admire this sort of person. The plucky “can do” atitude. Carry your own water. Cut your own wood.
CY starts the ball rolling by writing her own sort. Who does that? “Can do” people, that’s who. While she’s in there doing the work herself, fighting entropy one list at a time, she notes the difference between each pair of sorted elements as she holds them up, keeping a running tally of the largest she finds.
At the end of the sort she is left with the maximum. See? That wasn’t so hard.
if ($#N != 0) {selection_sort();}
print $max_dif, "\n";
sub max_ind {
my $max = $arr[0];
for my $i (1..$#arr) {
if ($arr[$i] > $max) {
return $max_i;
swap_arr_N(0, max_ind(@N));
for my $i (1..$#N) {
swap_arr_N($i, $i+max_ind(@N[$i..$#N]));
my $dif = $N[$i-1] - $N[$i];
$max_dif = $dif if $dif > $max_dif;
sub swap_arr_N {
($N[$_[0]], $N[$_[1]]) = ($N[$_[1]], $N[$_[0]]) if $_[0]!=$_[1];
Laurent’s solution is simplicity itself, so much that he reimplements his submission in a half a dozen other languages. Bravo. Here they are, for a comparative analysis:
…or as a map function
Abigail, Simon Green, Stuart Little, W. Luis Mochan, and Wanderdoc
Because of my unnatural fondness for listwise operators, when I first thought this challenge through I came up with using map to do my bidding. Iterating across the indices starting from 1, we look at each element and the one preceding and take the difference. This generates a list of differences, which we can then scan to find the maximum.
We do this all this after we sort, of course. We always sort. It is the way.
Simon shows how compact this idea can be, wrapping all three components into a single line, and even presenting it as a proper command line one-liner.
perl -E 'use List::Util "max"; my @a = sort { $a <=> $b } @ARGV; say max(0, map { $a[$_] - $a[$_-1] } (1 .. $#a) )' <DIGITS>
Taking ever-so-slightly more room to make his case, Abigail presents the logic in a similarly compact form. Bit more readable this way, I’d say. I like a little air in the code. YMMV.
Luis brings us a little variation, using reduce from List::Util to construct his own max function from base components, always keeping and passing through the larger of the two values examined.
or alternately, ITERATING over the VALUES
We can just loop over the values themselves. As we know we’re going to look at every pair of elements we don’t really need or care about the specific index values themselves. We only need to know the value of whatever element we looked at previously so we can compare it to the current one.
…with either a for loop
James Smith, Lubos Kolouch, Mohammad S Anwar, and Peter Mayr
James unrolls what is basically the action of a reduce function in his max_gap() subroutine, examining each element of the sorted array in turn against a stored previous element. At the end of the comparison the current element replaces the stored previous and the next element is examined.
my( $max, $p, @sorted ) = ( 0, sort { $a <=> $b } @_ );
# Shift off first value ($p), we will loop through @sorted and
# compare the difference between value and previous value ($p).
# At the end of each iteration we will replace $p with the next
# value
# This saves us having to loop through elements using an index
# and calculating - $sorted[$_+1]-$sorted[$_]..
$max = $_ - $p if $_ - $p > $max;
$p   = $_;
…or by using map with a block
Flavio constructs his map with a twist: like James, he maintains the previous value through each iteration to make the comparison with this next. In this way he doesn’t need to iterate across the indices, instead using the values themselves. At each loop the difference is calculated with the previous, the current is saved to the previous, and the difference returned in the processed list. The maximum value in this list is the maximum gap.
…or even shifting the array out from underneath
Adam first sorts his list, of course, and then applies an unusual little construction: a recursive routine which finds the gap between the first two elements, then trims the list one element from the beginning and calls itself again. At each stage the gap is chosen to be the larger of the gap found between the first elements and that returned by the recursion. Thus the largest gap will propagate through as the recursion finishes and collapses, providing the result.
THEN AGAIN, we could even ITERATE in some OTHER, UNUSUAL way
Colin Crain, Jorg Sommrey, Niels van Dijke, and Ulrich Rieke
Ulrich gives us a intermediary routine, createPairs(), which breaks the sorted array down into tuples of element neighbors. Elements from the interior indices are hence represented twice, in two pairs: one as a left-hand element, the other as a right. The gap is thus the difference between the two items in the pair.
sub createPairs {
my $numbers = shift ;
my $len = scalar @{$numbers} ;
my @pairs ;
for my $i (0 .. $len - 2 ) {
push @pairs , [ $numbers->[$i] , $numbers->[$i + 1]] ;
return @pairs ;
my @sorted = sort { $b <=> $a } @numbers ;
my @pairs = createPairs( \@sorted ) ;
my @differences = sort { $b <=> $a } map { ${$_}[0] - ${$_}[1] } @pairs ;
say $differences[ 0 ] ;
When I first thought out this challenge, my mind went to map, as I can see was often the case. The obvious problem that arises immediately is that map applies a function over individual elements in a list, and here we have to compare two elements, each element to its neighbor. The ways to get around this are, as we have seen, either to map across the indices of the array, looking up the index to get the value and subtracting 1 from the index to get the neighbor, or keeping tabs on whatever the previous value was so we cn reuse it. Either way we can use this method to digest a list into a list of differences, and then go find the largest value from that.
But let’s return to map and its fundamental nature of only applying a function to one element at a time. Wouldn’t it be great to be able to apply a function, as map does, over pairs of adjacent elements directly? Well, there is another option, reduce, that sort of does that. For those that do not know, reduce does take a binary function as its argument, sort of. It acts on two internal parameters, $a and $b, only it automatically places the result of its actions into $a for the next iteration, drawing only a single new value from the list as $b. So the binary operation part sounds like something we could use, but the assignment of the result to $a is a little sticky. We can subtract $a from $b to get our difference (of a sorted array), and then put $b into $a by making it the result, allowing us to compare the next pair of elements when we draw the next value into $b. But then where do we keep our comparison? We need another variable.
The thing is — anything can be in our block, including anything in scope when we call reduce. If we declare our $gap accumulator there, we can look at it to get our result when we’re done.
sub gap_reduce (@list) {
reduce { $gap = $b - $a if $b - $a > $gap; $b } sort {$a<=>$b} @list;
This works well and there’s nothing wrong with it. But there is one thing, in that we seem to be somehow missing the point: reduce works over a list to use those values to compute a new value from the elements. When we are done, we have reduced a list to a single value, hence the name. What we’ve done here instead is to create a side effect of noticing the largest difference between values as the list is being processed en passant, then thrown away the result of the iterations and just kept the side effect. This whole idea rubs some people, functional purists you might say, the wrong way.
That last bit is a little play on words because a function that has no side effects outside its immediate scope — it makes no interactions with the world outside its parameters and return value — is called a “pure” function. And the block we’ve defined isn’t pure, it needs $gap to report its findings. The function gap_reduce() is pure, but the block called in the reduce is not. This really only matters if you want to strictly apply this credo of functional programming — that functions are discrete units that perform their actions in a defined, repeatable way independant of the state of the outside world they live within.
I admit it annoyed me, and so I went on to also implement the map index method outlined above. As the indexes of an array are an integral part of the data structure this map can be said to take a function and a list and output a list of differences between values, which we can then find the maximum of. Everything is pure.
I did go back some time later and revisit the problem, making the block given to reduce properly pure. It’s more complex now, lacking the elegance of the original. We keep $gap within the block, and only output it in the last iteration. This involves keeping another variable to count indexes, so either $b is the last result, to be placed into $a for the next cycle, or $gap, which being the final value is returned.
You can probably tell I like reduce a lot. It’s a fun concept to play with.
## version 3 - reduce redux
sub gap_reduce_redux (@list) {
scalar @list > 1 ? reduce { my $gap //= 0;
my $idx++;
$gap = $b - $a if $b - $a > $gap;
$idx == @list-1 ? $gap : $b
} sort {$a<=>$b} @list
Jorg gives us a sort in void context, which is not a construction I can ever recall seeing before. From that odd beginning we see how he harnesses a side effect inside the sort block to find the gaps. No matter what other comparisons are made for a given element, each must be compared at some point against its final neighbors, right? So, as the gap between smaller and larger is an absolute value we need only consider half the gaps, and we choose those going upward to a higher value. By taking the smallest of these gaps as the a hash value keyed to a given element, we end up storing the distance to its closest higher neighbor, the next rightward when sorted. This hash will end up with keys for every element save the highest, and the largest value in this hash will be the maximum gap between elements.
# Regardless of the sorting algorithm in use, every pair of neighboring
# elements must be compared in the process.  Otherwise the succession of
# such pair would remain undetermined.  Finding the gaps as mimimum
# differences while comparing and taking the maximum thereof afterwards.
my %gap;
# Discard the sort result.
my ($l, $h) = $a < $b ? ($a, $b) : ($b, $a);
# Considering different values only.
$gap{$l} = min $h - $l,  ($gap{$l} // 'inf') if $h > $l;
$a <=> $b} @_;
(max values %gap) // 0;
There’s another list-processing function available, this one in List::MoreUtils that takes a binary operation, and that’s pairwise. Unfortunately this doesn’t take from a single list, but rather takes two lists, drawing one element from each and supplying the given BLOCK with the values. This is great obstacle; all Niels need do is restructure his data as a pair of array slices with a 1-index offset. Then each value will be compared with the next along, and the largest of thes calculated values is the maximum gap.
my @i = sort { $a <=> $b } @_;
my @p1 = @i[0 .. scalar(@i)-2];
return max(pairwise { $b - $a } @p1, @p2);
When researching List::MoreUtils, I found that since version 0.430, released Oct 21 2020, there’s now a function slide that “slides” across a list exactly as we need it to, applying a binary operation to each pair of values as it goes. From the docs:
Sweet. So to roll up a quick solution:
use List::MoreUtils qw(slide);
use List::Util      qw(max);
say max slide { $b - $a } sort {$a<=>$b} @input;
Input:  $N = 1, $D = 3
Input: $N = 1, $D = 2
Abigail, Adam Russell, Athanasius, Cheok-Yin Fung, Colin Crain, E. Choroba, Flavio Poletti, James Smith, Jorg Sommrey, Laurent Rosenfeld, Niels van Dijke, Roger Bell_West, Simon Green, Stuart Little, W. Luis Mochan, and Wanderdoc
There were only 16 working solutions for the second task this past week. The overwhelming choice in technique was implementing some form of long division algorithm to divide the numerator by the denominator, keeping track of and monitoring the remainder portion at each step to notice either a 0 — indicating an even division had been made — or a remainder that had previously been seen, indicating that a loop cycle was complete. The schemes to implement this all shared a common similarity, albeit cast through personal idiosyncrasies.
The second most common method attempted was to parse out a repeating decimal with a regular expression. This was complicated by both floating point accuracy, which could produce incorrect digits in the division, and by the the puzzle of correctly discriminating a repeating final reptend from other simple repeating sequences that could arise.
In addition, there were some more mathematically theoretical submissions. We’ll be having a look at those as well, alongside a very interesting port from the Raku source-code of the .base-repeating method available in that sister language.
the CRITERIA
This challenge yet again put me in the difficult situation of having to decide, against a rather simple and open-ended specification, whether a given method works or not. The obvious item to search for is the correct identification of a repeating decimal, but as these can be quite long other factors such as the accuracy of floating point numbers can come into play in that evaluation.
It stands to reason, then, that any solution based on using standard, floating-point division can be broken by tossing enough complexity at it.
My sources tell me, for instance, that 1/5714207 has a reptend that’s 5714206 digits long. That’s a lot of significant digits. I’m not going to check that result, but you get my point. So although this is a valid consideration, it does seem wrong to throw out every answer that uses built-in division on this basis. Where then, do I draw the line?
The above fraction takes a few seconds for me to compute, and even a noticeable amount of time to display after it’s done. For the fraction 1/<PHONE>, well, I imagine it would eventually give an answer — there’s no reason besides my impatience with a control key that it wouldn’t. And that’s only the 50,000,000th prime. There’s plenty more where that came from. So of course we can “break” any algorithm that way as well, by exceeding the power of whatever machine we use to run it.
On the other hand we have 1/17th. This fraction has a 16 digit reptend and is pretty low on the big list of fractions. It seems like a pretty reasonable thing to expect from a repeating decimal program. It’s also the smallest big reptend, you might say, in the class of repetends having k-1 digits for a given fraction 1/k. 7 is like that, with the 6 digits in its familiar 142857 string, but I don’t consider that very large. This is like that too, being the next larger version, followed by 1/19 and 1/23. This class of numbers, incidentally, are known as Full Reptend Primes. 5714207, you might have noticed, would be in there too.
So I went through and ran 1/17 to see if it gave “0.(<DIGITS>)". That was the first big test.
The second test I landed on was less obvious, but that was 1/44 = 0.02(27). This is tricky because it has a repeat that isn’t comprised of leading 0s, being that pair of 2s. Sadly, a few solutions that otherwise looked to be correctly handling things found these and short-circuited, giving the answer 0.0(2).
So what was deemed ok, then? Well one thing that wasn’t commonly implemented was support for negative numbers. Because the main technique employed makes extensive use of Euclidean division, these values caused all kinds of problems with the ceiling versus the floor, and the result is the whole plan doesn’t work unless active steps are made to accommodate them. In fact only four people did. On this basis I decided we wouldn’t care too much about that, as any added robustness seemed being pretty tangental to the main logic anyway. My life is complicated enough; I have no need for an angry mob with pitchforks added to it.
One oddity I saw more than once was seeing 1/17 as 0.0(<DIGITS>). Note the trailing 0. While not necessarily the most compact, or best way to say it, I can’t really say it’s wrong, either. It is, after all, mathematically equivalent, much as the value 1 can be written 1.0 or even 1.(0) if one had some deep need to do so. I recall running into this problem myself, and eventually reworked my answer until it went away. It’s also interesting to me because in both cases it’s cited to be from what appears to be the same python source.
Abigail, Adam Russell, Cheok-Yin Fung, Colin Crain, E. Choroba, Flavio Poletti, Laurent Rosenfeld, Niels van Dijke, Roger Bell_West, Simon Green, W. Luis Mochan, and Wanderdoc
The most common approach to the solution was to implement a version of long division, breaking the larger problem into a sequence of steps involving Euclidean division and pulling down additional decimal 0s from the numerator to the remainder to make each successive step.
We’ll look to Niels to start us off today. Here is his example of the long division logic. At each iteration we add enough zeros to the current remainder to make it greater than the denominator. With this value as the new numerator we store it in a hash against its position, being the current length of the result string we are constructing. Integer division is then performed on the new numerator and the denominator, with the integer portion added to the result string. This continues until either the remainder becomes 0 or is recognized as a key in the %rSeen hash.
If the remainder is found in the hash, the position stored in the value will indicate the beginning of the repeat.
while ($n < $d) {
$n .= '0';
$result .= '0' if ($n < $d);
push(@{$rSeen{$n}}, length($result));
$result .= int
if (scalar(@{$rSeen{$n}}) < 2);
$r = $n % $d;
} while ($r != 0 and scalar(@{$rSeen{$n}} < 2));
Here are the same steps presented by Simon in a slightly different manner. The progress is systematic and straightforward.
while ( $N != 0 and not exists $seen{$N} ) {
# Repeat the division until we've seen a remainder
$seen{$N} = length($digits);
( my $digit, $N ) = _div( $N, $D );
$digits .= $digit;
if ( $N == 0 ) {
# It's not a repeating number
say $digits ? "$whole.$digits" : $whole;
# Add the parenthesis in the correct place, and display the number
substr( $digits, $seen{$N}, 0, '(' );
say "$whole.$digits)";
For my own solution, I used an explicit position counter that logged every remainder seen to its position, whether it had enough zeros added or not. After dancing around the problem for a while and later refactoring out a certain amount of cruft I ended up quite pleased at the simple structure of the final result.
sub ediv ( $num, $den ) {
## Euclidean division of $num by $den returns quotient and remainder
(int( $num / $den ), $num % $den);
my ($whole, $r) = ediv( $num, $den );
while ($r != 0) {
## add one 0 to remainder
## add remainder at every index position to %seen hash
exists $seen{$r} ? last : ($seen{$r} = $pos);
## add additional 0s to remainder and quotient until num > den
## with each 0 increment index position and add to seen hash
until ($r - $den >= 0) {
push @q, 0;
## the long division step
($q, $r) = ediv($r, $den);
push @q => $q;
## three cases:
## * whole number, no decimal
## * isolate and present repeating fraction in parens
## * finishes neatly, join with decimal point
$out = $whole;
elsif ($r) {
my $start   = $seen{$r};
my $end     = $pos-1;
my @pre     = @q[0..$start-1];
my @rep     = @q[$start..$end];
$out = join '', $whole, '.', @pre, '(', @rep, ')';
$out = join '', ($whole, '.', @q);
Adam shares a lot of submissions with us in Prolog, and his proclivities show through in his attachment to the logical purity of a nice true or false result. This is perhaps a bit of observational speculation on my part, but in any case he imports the boolean pragma to give him these barewords.
Here he employs a computational switch to avoid looking for a reptend unless the numerator contains prime factors other than 2 and 5. His prime_factor() function does what you’d expect.
Any other prime factor beyond 2 or 5 will produce a repeating decimal, and if this is the case he then performs long division to find a matching remainder using a hash:
It seems both Roger and Laurent have adapted the same Python solution for their submissions; a fact I know for sure because they properly cite their common source. To me the amusing part was that I didn’t pick up on this right away from their respective blog writeups, but rather from a shared notational oddity in their results: yielding “0.0(<DIGITS>)” for 1/17th rather than “0.(<DIGITS>)".
Here’s Roger’s version. From personal experience I found getting rid of that trailing zero shift without breaking other parts to be quite a bother, and it was the simplifying and indiscriminately caching of every remainder examined, whether it was larger than the denominator or not, that ultimately made it go away. Less code, in my case, rather than more. For this version? Who knows.
my $quotient = sprintf( '%d.', $n / $d );
my $c = 10*( $n % $d );
while ( $c > 0 && $c < $d ) {
if ( exists $passed{ $c } ) {
my @cycle = @digits[$passed{ $c }..$#digits];
my $result = $quotient . join( '', @digits[0..$passed{ $c }-1] );
if ( scalar @cycle > 1 || $cycle[0] != 0 ) {
$result .= '('. join( '', @cycle ) .')';
if ( substr( $result, -1, 1 ) eq '.' ) {
substr( $result, -1, 1 )='';
my $q = int( $c / $d );
my $r = $c % $d;
$passed{ $c }=$i;
push @digits, $q;
$c = 10 * $r;
Choroba shares another fine example of long division with a lookup hash for the remainders, with the added bonus of having accommodation for negative numbers. As these complicate Euclidean division, turning floor operations into ceiling and thus no longer allowing us to substitute integer truncation, he neatly sidesteps the issue by removing the signs and properly replacing them after all is over and done.
sub decimal_string {
my ($abs_n, $abs_d) = map abs, $n, $d;
my $result = join "",
($n < 0 xor $d < 0) ? '-' : "",
int($abs_n / $abs_d),
my %seen = (my $remainder = $abs_n % $abs_d => 0);
while ($remainder != 0) {
$remainder *= 10;
$result .= my $r_digit = int($remainder / $abs_d);
my $new_remainder = $remainder % $abs_d;
if (exists $seen{$new_remainder}) {
substr $result,
1 + index($result, '.') + $seen{$new_remainder},
0, '(';
return "$result)"
$seen{ $remainder = $new_remainder } = $i++;
return $result =~ s/\.$/.0/r
Finally, Flavio provides us with what is perhaps the most exhaustive solution using long division, not only allowing for negative input but also delivering a reverse function to test his work, able to produce a fraction from a parsed-out repeating decimal. So to switch things up a bit, rather than share his long division we’ll have a look at this unusual turn of events.
The basic idea here is to create a fraction of the reptend over a number made up of an equivalent number of “9” digits, with allowances made for a non-repeating transient before the reptend.
Interested parties might wish to read the wikipedia article on the process. Make a note of this technique — we will see it resurface later.
matching out the REPTEND using a REGEX
Alternately, several members attempted to match out repeating sequences using a regular expression. This proved remarkably difficult to get right, due not only to the aforementioned problems with floating point precision and premature matching but also with the problem that the last digit calculated might not be the last digit of the reptend. Ultimately only James was able to overcome these obstacles.
James sidesteps the accuracy of floating point division by compacting a long division routine into a single complex line, calculating a decimal string twice the length of the denominator value. As:
the maximum period in the reptend for a value 1/k is k-1,
the size of the transient for 1/2a5b yields max(a,b) added digits, and
the period of c/k is the same as 1/k,
then we can conclude this is always enough digits to repeat the reptend at least once.
So at this point he knows he can safely match for some group of digits repeated at least once and anchored to the end of the string. This produces a reptend, but might not be the best way to write it. As we’re talking about a cycle, any arbitrary rotation of that cycle can define the continuance, as long as the offset digits are defined in the transient portion. The numbers 0.(142857), 0.1(428571), and 0.14285(714285) are equivalent — even if they aren’t written in the most compact form. It’s an infinite sequence. It doesn’t have a final digit.
There is a solution provided for his situation: he handles the case where the last digit rendered may not be the last digit of the repeating sequence by comparing the end of the non-repeating section again against rotations of the repeated sequence, shortening the transient and shifting and rotating the reptend in the process until no more digits can be removed. It seems to work.
I am sometimes torn a bit between leaving in James’ extensive commentary and slicing it out to highlight just how compact his solutions can be. On the other hand after such rarefaction having a roadmap is much appreciated and more than welcome, if not required. Cramming too much action into a single line as an end in itself can certainly lead to unnecessarily obscure results, but he seems to gain so much pleasure from it it’s infectious.
my( $D,    $whole_part,      $N,            $res ) =
( $_[1], int($_[0]/$_[1]), $_[0] % $_[1], ''   );
## "Long division" to arbitrary precision...
return $whole_part if $N == 0;
($res,$N) = $D>$N ?
: ($res.int($N/$D),($N%$D).'0')
foreach 0 .. 2*$D;
## Find a recurring sequence... and remove it!
## We look for the "shortest" sequence - but it must be tied to the
## RHS of our result string....
$res =~ s{(\d+?)\1+$}{}g;
my $recurring = $1;
## $recurring is the recurring digits - it may be "0"s in which case
## the number is represented by a finite
## As this is a recurring sequence tied to the end of the string, we
## need to look to see if we rotate it to see if it started earlier..
## So we compare the last letter of the string & the recurring
## string and if it matches we move it to the start of the recurring
## sequence and strip the last letter of both strings....
## (chomp $str).$str <- achieves this rotation....
## Note the little nastiness here - to make the while loop a
## one-liner we allocate $recurring to the first of the list of
## "list" on the RHS of the = sign and drop the other
($recurring) = (chop $recurring).$recurring, chop $res
while (substr $res,-1) eq substr $recurring, -1;
substr $res, 0, 1, "$whole_part."; ## Replace leading 0 with
## The whole part we removed
## above for dealing with N>D
$res .= "($recurring)" unless $recurring eq '0';
COPRIMES are PRIMES TOGETHER
Jorg Sommrey and Stuart Little
There were some rather intense mathematical solutions that worked on computing the number of digits in the reptend and isolating it out from there by various methods.
Here’s a little light reading to get you up to speed before you start:
Carmichael’s Lambda Function
Jorg solves the precision problems of floating point numbers by calculating his division using the BigRat and BigFloat data types. From there he computes a number of digits as given by Carmichael’s lambda function, which gives an upper limit of the length of the reptend. From there a regular expression is used to try and match out a shorter, repeating reptend should one be present. The length of any shorter reptend will evenly divide the result from the lambda function.
It’s all very well broken down, albeit some of the steps are performed in a very technical way that might not immediately be clear. For example, “Find the largest divisor in the denominator that is coprime to 10” just means divide out and remove all factors of 2 and 5 from the denominator. The triplet of steps he uses to accomplish this are artfully pure, with all of the functional indirection that might bring to mind. I find it a bit like reading a proof.
my %pow     = map {($_ => valuation $frac->denominator, $_)} factor 10;
my $nlen    = max values %pow;
my $coprime = reduce {$a->bdiv($b ** $pow{$b})} $frac->denominator, keys %pow;
We could have hard-coded a couple of loops, but where’s the fun in that? And to be sure, we do need $nlen later, to know how many zeros to add to the transient before the reptend. So there’s a solid reason to it all, complex as it is.
use Math::Prime::Util
qw(carmichael_lambda valuation fordivisors lastfor factor);
use List::Util qw(max reduce);
# Convert a fraction into its decimal representation, highlighting a
# repetend.
# We *could* perform a long division, record the occurring remainders
# after the numerator has been exhausted and stop at the first
# repetition.  But...
# Here is a different plan:
# Perform a BigRat division with a sufficient number of significant
# digits.  Then truncate the result at the end of a repetend and find
# the true repetend.  The required number of digits is composed of the
# integer part's length, the length of a non-repeating sequence and an
# estimate for the period, i.e. a (preferably small) multiple of it.
# The integer part is facile.
# For the length of the non-repeating sequence we have to find the
# powers of 2 and 5 in the denominator.  Each factor 2, 5 or 10 adds
# one digit.  Thus the length of the non-repeating sequence is the
# maximum exponent of 2 and 5 in the denominator.
# For an estimate of the period we need to find the largest divisor in
# the denominator that is coprime to 10, i.e. the denominator with all
# powers of the common factors removed.
# The period of the reciprocal of the coprime denominator cannot be
# larger than the maximum order of this reduced denominator as an
# element of the multiplicative group of integers modulo k (for any
# coprime k), which is given by Carmichael's lambda function.
# <URL>
# and <URL>
# Luckily the lambda function is provided by the awesome
# Math::Prime::Util module.
# Finally, put the actual repetend in parentheses.
# Create a fraction object.
my $frac = Math::BigRat->new(shift);
return "$frac" if $frac->is_int;
# Find the powers of 2 and 5 in the denominator and their maximum
# exponent.
my %pow = map {($_ => valuation $frac->denominator, $_)} factor 10;
my $nlen = max values %pow;
# Find the largest divisor in the denominator that is coprime to 10.
my $coprime =
reduce {$a->bdiv($b ** $pow{$b})} $frac->denominator, keys %pow;
# Get an estimate for the period of the reciprocal of the coprime
my $rlen = carmichael_lambda $coprime;
# Check the limit for quantifiers in regexp's.
die "period possibly too large, giving up" if $rlen >= 2 ** 15 - 1;
# Convert the BigRat via BigFloat into a string ending in the
my $decimal .= $frac
->as_float
->bfround(-($nlen + $rlen));
# The actual period is a divisor of the maximum period.  Try all
# divisors in ascending order up to the first match.
fordivisors {
# Number of repetitions.
my $rep = $rlen / $_ - 1;
# Enclose the repetend in parentheses or remove zeroes.
lastfor if $decimal =~
s/^.*?\..{$nlen}\K(.{$_})\1{$rep}$/"($1)" x !!$1/e;
} $rlen;
$decimal;
Stuart uses a completely different method to produce the reptend of his result, sharing similarities with the decimal to fraction conversion we saw earlier.
After using his ordExp() function to compute the number of digits, he multiplies the quantity of the numerator modulo the portion of the denominator coprime to 10 (that is, with all the 2s and 5s divided out), by a number composed of the digit-length of 9s, divided by the coprime denominator again. Yea, that took me some time to get through as well. Perhaps a visual aide will help. For example for the fraction 1/14 we evaluate the equation:
my $fract = int ((($num % $den) * (10**$digs-1))/$den);
fract = 5 ×
→ 5 × 142857
→ 714285
Neat, huh? The end result, by the way, is 0.0(714285). Calculating the the non-repeating portion of course adds its own additional wrinkle of complication.
sub ordExp($n,$p) {
my ($ord,$base)=(1,$n % $p);
while ($base-1 % $p) {
$base = ($base*$n) % $p;
sub when10copr($num,$den) {
my $int = int($num/$den);
my $digs = ordExp(10,$den);
return $int, ('0' x ($digs - length($fract))) . $fract;
sub fractPart($num,$den) {
my $exp2 = maxExp(2,$den);
my $newNum = ($exp2 >= $exp5) ? (5**($exp2-$exp5) * $num) : (2**($exp5-$exp2) * $num);
my @copr = when10copr($newNum, int $den/(2**$exp2 * 5**$exp5));
my $nonRep = ($copr[0] || max($exp2,$exp5)) ? ('0' x (max($exp2,$exp5) - length($copr[0])) . $copr[0]) : ("");
my $rep = ($copr[1] ne "0") ? (qq|($copr[1])|) : ("");
return $nonRep . $rep;
my ($num,$den) = @ARGV;
say int($num/$den) . "." . fractPart($num % $den,$den);
INTERESTING and UNUSUAL DEVELOPMENTS in the CASE
The monk opens by noting the absence of the handy Raku method .base-repeating, which makes the task quite straightforward in that language. Furthermore, they note the apparent lack of anything equivalent in CPAN to provide this from a module.
So they decided to port the Raku source code for the function, from the file
rakudo-2021.03/src/core.c/Rational.pm6
Raku relies on a native Rational (Rat) type here, so for the port the Core module Math::BigRat is brought in to provide the functionality. This technique handles negative numbers and also provides for arbitrary number bases, which is an interesting twist.


Might I plead – on behalf of, I am sure, many readers of your columns – that you declare this Saturday a day of rest.
A rest, that is, from the deluge of political correspondence from your faithful army of obsessives and paranoiacs we have suffered over many months.


Bynum starts, Bennett sits and Irving gets an earful from Brown in Cavs loss to Bulls
Derrick Rose and  Monday in Chicago. The Bulls won 96-81. (AP Photo/Charles Rex Arbogast)
CHICAGO: On the night Andrew Bynum made his first start of the season, top overall pick Anthony Bennett didn’t get off the bench and Kyrie Irving received an earful from his head coach.
Other than that, it was just another road loss for a team still searching for its first win away from home.
Bynum set season highs in minutes, points and rebounds, but the Chicago Bulls pulled away over the game’s final five minutes for a 96-81 win over the Cavs.
It was the first head-to-head matchup between the Cavs’ Kyrie Irving and the Bulls’ Derrick Rose, but it ultimately failed to meet expectations. Irving had 16 points and four assists, but missed his first six shots and didn’t get his first basket until the final minute of the third quarter. He ended the night 5 of 19, further lowering his anemic shooting percentage to 38 percent for the season.
Coach Mike Brown subbed him out with 3:13 left in the first quarter, then followed him down to the end of the bench and gave him an earful for the better part of a minute.
Irving didn’t offer any further details.
“Just a conversation with my coach,” he said. “That’s about it.”
Brown was aggravated the starters didn’t do a better job of involving Bynum in the offense, which clearly was the intended goal of moving him into the lineup. He f.
“We don’t know how to play with a guy like that,” Brown said. “Iwe had in the whole game, the ball went to him, they doubled, he kicked it to Dion (Waiters) for a wide open 3 on the weak side. But we don’t understand that yet. Hopefully we will soon.”
Brown made the lineup switch without practicing it first. Instead, he held a two-hour shootaround Monday morning and reiterated that right now, a lot of the Cavs practices are held during games while guys learn each other.
Bynum said his game doesn’t really change by becoming a starter, but it changes for the players around him.
“That’s just something we’re going to have to go over in practice. I’m not too familiar with all the plays they’ve put in and vice versa,” Bynum said. “I think we have a good practice planned for (Tuesday). We’ll.”
The Cavs trailed for much of the night, but remained within 78-75 on a basket from Irving with 4:55 left when the Bulls took over. The Bulls scored 13 of the game’s next 15 points, including seven from Mike Dunleavy, and the Bulls extended the lead to double figures in little more than a minute.
“They just mentally and physically did what they wanted to do to us,” Brown said. “Wl. Chf.”
Tristan Thompson had 14 points and 13 rebounds and Dion Waiters had 13 points and six turnovers.
Rose had 16 points and seven assists on 8 of 21 shooting.
Bennett was not listed as an injured player prior to the game and the Cavs said he was available to play, but Brown said he sat him all night because his shoulder was still bothering him. Bennett sprained his shoulder in Friday’s loss to the Philadelphia 76ers, but returned to play at home in Saturday’s win.
“His shoulder was bothering him in the last game some so I decided to sit him,” Brown said. “He may play next game, he may not. I wanted to give Henry (Sims) a shot, I thought Henry played well, too. I wanted to give Henry a shot.”
The Cavs will practice in Chicago on Tuesday before flying to Minneapolis. They’ll face the Minnesota Timberwolves on Wednesday. Shares


. The FARs provide an interface to the WAN backhaul to facilitate communication with the head-end systems.
NANs also serve as a foundation for future virtual power plants, which comprise distributed power generation stations, residential energy storage (for example, in combination with electric vehicle charging), and small-scale trading communities.
Communication in the Neighborhood Area Network (NAN), which consists of the connected grid end-points, is based on the open standards RF Mesh technology compliant with IEEE 802.15.4g-2012 and IEEE 802.15.4e-2012 and delivers bi-directional communication through an implementation of Internet Protocol suites such as the 6LoWPAN (RFC 6282) adaptation layer, native IPv6 addressing in the network layer, and RPL (IPv6 Routing Protocol for Lossy and Low Power networks), which is the protocol of choice for routing in the 6LoWPAN subnets. RPL route information gets re-distributed in the selected routing protocol for the WAN.
The CGR 1240 is provisioned with a WPAN module, which provides IPv6-based, IEEE 802.15.4g/e compliant wireless connectivity to enable Field Area Network applications. The module is ideal for standards-based IPv6 multi-hop mesh networks and long-reach solutions. It helps enable a high ratio of endpoints to the CGR. The WPAN module is aligned with the Wi-SUN alliance’s objectives for smart utility grids.
The CGR 1240 can act as an aggregation point for a few thousand meters. Capacity planning should be carried out while deploying a field area network in order to determine the number of meters that can be associated with the CGR in a single PAN. </s> Translation Disclaimer
T Graduate Schools in Hayward, California
There are at least 0 colleges in Hayward,
21615 Hesperian Boulevard
Hayward, WI <ion.
Can we achieve this seismic shift toward bullying?
First-time author Jason Kendal was frustrated because he was unable to help his younger sister, Jacquelyn, who was often bullied at school. He believes the key to breaking the cycle is to introduce the conversation to a much younger audience.
Jacquelyn Kendal, the inspiration behind My Friend Clyde, says: “When I was being bullied I always wondered why this was happening to me, and why I had to be the one who was different. Not only did I feel upset, angry and lonely but I blamed myself for how I was treated. It took a long time but I have finally accepted the person I am today. I can’t make people treat me nicely but I can make sure that I am good to others. I will always have a learning disability but that is not all that I am.” Jacquelyn broadens the reach of the message by facilitating book readings at school.
The news is time sensitive, not only because the statistics on the repercussions of bullying – including suicide – are alarming, but because the book is part of a Kickstarter campaign. The Kendals need to raise $6,050 to publish the book – including 500 copies to be donated to schools, libraries and non-profits – and to complete an accompanying interactive website. A portion of all sales will be directed to anti-bullying not-for-profit causes. This particular campaign operates uMy Friend Clyde p this book will not see the light of day.
We have an immensely diverse range of housing stock within the UK. In our rural villages, 40% of all homes were built before 1919, with some dating back many centuries. The fact they are still here and valued today is testament to both their architecture and their traditional construction from solid stone and brick. These are highly sought after propertiHowever, thousands of these period


Blake has made many improvements since starting hyperbaric oxygen therapy for his spinal cord injury. Hyperbaric Oxygen can play a vital role in the treatment and recovery of a spinal cord injury. His testimonial says it all!
Before every game, Rashad Jennings cannot contain himself as he shouts to his teammates, "Don't let anybody define you!''