It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
import math

year = int(input())

year += 1
amigo = True

while amigo:
    primer = math.floor(year / 1000) % 10
    segundo = math.floor(year / 100) % 10
    tercero = math.floor(year / 10) % 10
    cuarto = math.floor(year) % 10
    if primer != segundo and primer != tercero and primer != cuarto and segundo != tercero and segundo != cuarto and tercero != cuarto:
        amigo = False
        break
    year +=  1

print(year)

