It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
# Get the input year from the user
input_year = int(input())

# Function to check if a year has distinct digits
def has_distinct_digits(year):
    return len(set(str(year))) == 4

# Increment the year until we find a year with distinct digits
while True:
    input_year += 1
    if len(set(str(input_year))) == 4:
        break

# Print the result
print(input_year)
