It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
num = int(input())  # Input the year as an integer

def has_distinct_digits(year):
    digits = set()  # Set to store the unique digits
    while year > 0:
        digit = year % 10
        if digit in digits:
            return False
        digits.add(digit)
        year //= 10
    return True

num += 1  # Increment the year

while not has_distinct_digits(num):
    num += 1

print(num)
