It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def has_distinct_digits(year):
    """
    Returns True if the given year has distinct digits, False otherwise.
    """
    return len(set(str(year))) == 4

def find_next_distinct_year(year):
    """
    Finds the minimum year number that is strictly larger than the given one and has only distinct digits.
    """
    year += 1
    while not has_distinct_digits(year):
        year += 1
    return year

# Example usage:
y = int(input(""))
next_distinct_year = find_next_distinct_year(y)
print(next_distinct_year)  # Output: 2014
