It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
# Beautiful Year

year = int(input())

while True:
  year += 1

  if (list(str(year))[0] != list(str(year))[1]) and (list(str(year))[0] != list(str(year))[2]) and (list(str(year))[0] != list(str(year))[3]):
    if (list(str(year))[1] != list(str(year))[2]) and (list(str(year))[1] != list(str(year))[3]):
      if (list(str(year))[2] != list(str(year))[3]):
        print(year)
        break
