It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
# Read the input year
y = int(input())

# Function to check if a year has distinct digits
def has_distinct_digits(year):
    digits = set()
    while year > 0:
        digit = year % 10
        if digit in digits:
            return False
        digits.add(digit)
        year //= 10
    return True

# Find the next year with distinct digits
while True:
    y += 1
    if has_distinct_digits(y):
        print(y)
        break
