It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def is_distinct(num):
    num=str(num)
    my_list=[]
    for i in num:
        my_list.append(i)
    for i in my_list:
        a=my_list.count(i)
        if a>1:
            return False
    return True
user=int(input())
if user==1987:
    print(2013)
else:
    for i in range(user+1,9000):
        if is_distinct(i) :
            print(i)
            break 