It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def has_distinct_digits(year):
    digits = set()
    for digit in str(year):
        if digit in digits:
            return False
        digits.add(digit)
    return True

def find_next_year_with_distinct_digits(y):
    next_year = y + 1
    while not has_distinct_digits(next_year):
        next_year += 1
    return next_year

if __name__ == "__main__":
    try:
        y_input = int(input())
        if 1000 <= y_input <= 9000:
            result = find_next_year_with_distinct_digits(y_input)
            print(result)
        else:
            print("Invalid input. Year number must be between 1000 and 9000.")
    except ValueError:
        print("Invalid input. Please enter a valid year number.")
