Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.

But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find the maximum possible least common multiple of these three integers?
The first line contains an integer *n* (1 ≤ *n* ≤ 10<sup class="upper-index">6</sup>) — the *n* mentioned in the statement.
import sys,random,bisect
from collections import deque,defaultdict,Counter
from heapq import heapify,heappop,heappush
from math import gcd
from types import GeneratorType
#from functools import cache  3.9
mod = int(1e9 + 7)
inf = int(1e20)
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
ii = lambda :int(input())
py = lambda :print("YES")
pn = lambda :print("NO")


n=ii()

if n<=2:
    print(n)
elif n%2==1:
    print(n*(n-1)*(n-2))
else:
    print(n*(n-1)*(n-3))