It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def check(y):
    lst = [int(i) for i in str(year)]
    cnt = 0
    for i in range (0,3):
        for j in range(i + 1, 4):
            if lst[i] == lst[j]:
                cnt += 1
    if cnt != 0:
        y += 1
        check(y)
    else:
        print(y)
y = int(input())
check(y + 1)