One day *n* cells of some array decided to play the following game. Initially each cell contains a number which is equal to it's ordinal number (starting from 1). Also each cell determined it's favourite number. On it's move *i*-th cell can exchange it's value with the value of some other *j*-th cell, if |*i* - *j*| = *d*<sub class="lower-index">*i*</sub>, where *d*<sub class="lower-index">*i*</sub> is a favourite number of *i*-th cell. Cells make moves in any order, the number of moves is unlimited.

The favourite number of each cell will be given to you. You will also be given a permutation of numbers from 1 to *n*. You are to determine whether the game could move to this state.
The first line contains positive integer *n* (1 ≤ *n* ≤ 100) — the number of cells in the array. The second line contains *n* distinct integers from 1 to *n* — permutation. The last line contains *n* integers from 1 to *n* — favourite numbers of the cells.
n=int(input())
A=list(map(int,input().split()))
P=list(map(int,input().split()))

# UnionFind

Group = [i for i in range(n+1)] # グループ分け
Nodes = [1]*(n+1) # 各グループのノードの数

def find(x):
    while Group[x] != x:
        x=Group[x]
    return x

def Union(x,y):
    if find(x) != find(y):
        if Nodes[find(x)] < Nodes[find(y)]:
            
            Nodes[find(y)] += Nodes[find(x)]
            Nodes[find(x)] = 0
            Group[find(x)] = find(y)
            
        else:
            Nodes[find(x)] += Nodes[find(y)]
            Nodes[find(y)] = 0
            Group[find(y)] = find(x)

for i in range(n):
    A[i]-=1
    if i+P[i]<n-1:
        Union(i,i+P[i])
    if i-P[i]>=0:
        Union(i,i-P[i])

flag=1

for i in range(n):
    if find(i)!=find(A[i]):
        flag=0

if flag==1:
    print("YES")
else:
    print("NO")
