It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def has_distinct_digits(year):
    # Convert the year to a set to check for distinct digits
    digit_set = set(str(year))
    
    # If the length of the set is equal to 4, all digits are distinct
    return len(digit_set) == 4

# Read the input
y = int(input())

# Increment the year until a year with distinct digits is found
while True:
    y += 1
    if has_distinct_digits(y):
        break

# Print the result
print(y)
