It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
# Online Python compiler (interpreter) to run Python online.
# Write Python 3 code in this online editor and run it.

year = int(input())
ogYear = year
ansFound = False
incr = 1
year = ogYear
while not ansFound:
    isYear = True
    year = ogYear+incr
    hashmap = {} # {number:times}
    while year > 0:
        rem = year%10
        if rem in hashmap:
            isYear = False
            break
        else:
            hashmap[rem] = 1
        year = year//10;
    
    if isYear == True:
        print(ogYear+incr)
        ansFound = True
    incr += 1