It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def check(n) :
    n1 = n
    sec = set({})
    while n!=0 :
        sec.add(n%10)
        n//=10
    if len(sec) == len(str(n1)):
        return True
    return False
n = int(input())
for i in range(n+1,9000+1):
    if check(i):
        print(i)
        break