It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def check(x):
    s = set()
    while x:
        r = x % 10
        if r in s:
            return False
        s.add(r)
        x //= 10
    return True

n = int(input())

for i in range(n + 1, 1000000):
    if check(i):
        print(i)
        break
