It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
year = int(input())
output = 0
flag = False
def count(year):
    list_ = list(str(year))
    count = 0
    l1 = []
    for i in range(len(list_)):
        if list_[i] in l1:
            continue
        else:
            count += 1
            l1.append(list_[i])
    return count
while flag == False:
    if year < 2013 and year >= 1987:
        output = 2013
        flag = True
    else:
        year += 1
        if count(year) == len(str(year)):
            output = year
            flag = True
        else:
            flag = False
print(output)