It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
# -*- coding: utf-8 -*-
"""
Created on Mon Sep 25 17:15:13 2023

@author: 25419
"""

year=int(input())+1
str1=str(year)
for i in range(9000):
    if str1[0]!=str1[1] and str1[2]!=str1[3] and str1[1]!=str1[2] and \
    str1[2]!=str1[0] and str1[0]!=str1[3] and str1[1]!=str1[3]:
        print(year)
        break
    else:year=year+1
    str1=str(year)
    continue