It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n=int(input())
def diff(n):
    d={}
    while n>0:
        r=n%10
        if r in d:
            return False
        else:
            d[r]=1 
        n=n//10
    return True
n+=1 
while True:
    if diff(n):
        print(n)
        break
    n=n+1 
    