We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.

You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not.
The first line contains a single positive integer, *n* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>), showing how many numbers are in the array. The next line contains *n* space-separated integers *x*<sub class="lower-index">*i*</sub> (1 ≤ *x*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">12</sup>).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.
import math as m

n = 100000
is_prime = [True] * (n + 1)
is_prime[0], is_prime[1] = False, False

for i in range(2, int(n ** 0.5) + 1):
    if is_prime[i]:
        for j in range(i * i, n + 1, i):
            is_prime[j] = False

n = int(input())
nums = [int(i) for i in input().split()]

for i in nums:
    if int(m.sqrt(i)) == m.sqrt(i):
        if is_prime[int(m.sqrt(i))]:
            print('YES')
        else:
            print('NO')
    else:
        print('NO')
  