It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
import sys
import math
import copy
from collections import deque
from collections import *

input = lambda: sys.stdin.readline().rstrip("\r\n")


def ll(): return list(map(int, input().split()))


def lf(): return list(map(float, input().split()))


def ls(): return list(map(str, input().split()))


def mn(): return map(int, input().split())


def nt(): return int(input())


def ns(): return input()
k=nt()
d=[]
for _ in range(k+1,9000+1):
    d=[]
    st=set()
    l=str(_)
    for x in range(4):
        d.append(l[x])
        st.add(l[x])
    if len(st)==len(d):
        print(_)
        break
