It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def has_distinct_digits(year):
    # Convert the year to a string to check for distinct digits
    year_str = str(year)
    # Use a set to keep track of the digits seen so far
    digit_set = set()
    for digit in year_str:
        if digit in digit_set:
            return False
        digit_set.add(digit)
    return True

def find_next_distinct_year(year):
    while True:
        year += 1
        if has_distinct_digits(year):
            return year

# Read the input year
y = int(input())
# Find the next year with distinct digits
result = find_next_distinct_year(y)
# Print the result
print(result)
