Permutation *p* is an ordered set of integers *p*<sub class="lower-index">1</sub>,  *p*<sub class="lower-index">2</sub>,  ...,  *p*<sub class="lower-index">*n*</sub>, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p*<sub class="lower-index">*i*</sub>. We'll call number *n* the size or the length of permutation *p*<sub class="lower-index">1</sub>,  *p*<sub class="lower-index">2</sub>,  ...,  *p*<sub class="lower-index">*n*</sub>.

The decreasing coefficient of permutation *p*<sub class="lower-index">1</sub>, *p*<sub class="lower-index">2</sub>, ..., *p*<sub class="lower-index">*n*</sub> is the number of such *i* (1 ≤ *i* &lt; *n*), that *p*<sub class="lower-index">*i*</sub> &gt; *p*<sub class="lower-index">*i* + 1</sub>.

You have numbers *n* and *k*. Your task is to print the permutation of length *n* with decreasing coefficient *k*.
The single line contains two space-separated integers: *n*, *k* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 0 ≤ *k* &lt; *n*) — the permutation length and the decreasing coefficient.
# python3
import sys, threading, os.path
import collections, heapq, math,bisect
import string
from platform import python_version
import itertools
sys.setrecursionlimit(10**6)
threading.stack_size(2**27)

def main():
    if os.path.exists('input.txt'):
        input = open('input.txt', 'r')
    else:
        input = sys.stdin
    #--------------------------------INPUT---------------------------------
    a,k= list(map(int, input.readline().split()))
    sol = []
    for i in list(range(k+1,0,-1))+list(range(k+2,a+1)):
        sol.append(i)
    output =' '.join(map(str, sol))
    #-------------------------------OUTPUT----------------------------------
    if os.path.exists('output.txt'):
        open('output.txt', 'w').writelines(str(output))
    else:
        sys.stdout.write(str(output))


if __name__ == '__main__':
    main()
#threading.Thread(target=main).start()