Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.

But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find the maximum possible least common multiple of these three integers?
The first line contains an integer *n* (1 ≤ *n* ≤ 10<sup class="upper-index">6</sup>) — the *n* mentioned in the statement.
from sys import stdin, stdout
import math

N=int(stdin.readline())
if(N>2):
    if(N%2==1):
        l=N*(N-1)*(N-2)
    else:
        if(N%3==0):
            l=(N-1)*(N-2)*(N-3)
        else:
            l=(N)*(N-1)*(N-3)
    stdout.write(str(l)+"\n")
elif(N==3):
    stdout.write("6\n")
elif(N==2):
    stdout.write("2\n")
elif(N==1):
    stdout.write("1\n")