It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def has_distinct_digits(year):
    # Convert the year to a string to check for distinct digits
    digits = str(year)
    return len(set(digits)) == len(digits)

def find_next_distinct_year(year):
    # Increment the given year
    year += 1

    # Keep checking for distinct digits until a suitable candidate is found
    while not has_distinct_digits(year):
        year += 1

    return year

# Test the function
given_year = 2013
result_year = find_next_distinct_year(given_year)
print("The minimum year with distinct digits after {} is: {}".format(given_year, result_year))
