It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
import math
n = int(input())
solve = True
n = n + 1
a = math.floor(n/1000)
b = math.floor(n/100) - 10 * a
c = math.floor(n/10) - 100 * a - 10 * b
d = n % 10
while solve == True:
    if a != b and a != c and a != d and b != c and b != d and c != d:
        break
    else:
        n += 1
        a = math.floor(n/1000)
        b = math.floor(n/100) - 10 * a
        c = math.floor(n/10) - 100 * a - 10 * b
        d = n % 10
print(n)