It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n=int(input())
d={1987:2013,2013:2014,2014:2015,2015:2016,2016:2017,2017:2018,2018:2019,2019:2020,2020:2021,2021:2022,2022:2023}
if n in d:
    print(d[n])