It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def good(n):
    aa=[]
    re=0
    for i in range(len(str(n))):
        a=n%10
        aa.append(a)
        n=n//10
    for j in range(len(aa)-1):
        for k in range(j+1):
            if aa[j+1]==aa[k]:
                re=1
    if re==1:
        return(1)
    else:   return(0)
    
begin=int(input())
ans=begin+1
while good(ans)==1:
    ans+=1
print(ans)