We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.

You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not.
The first line contains a single positive integer, *n* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>), showing how many numbers are in the array. The next line contains *n* space-separated integers *x*<sub class="lower-index">*i*</sub> (1 ≤ *x*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">12</sup>).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.
limit = 1000000
def calculate_prime_flag_for_each_number_upto_limit():
    prime_flag = [True] * limit
    prime_flag[0] = prime_flag[1] = False
    for i in range(2,limit):
        if prime_flag[i] == True:
            for j in range(i*i, limit, i):
                prime_flag[j] = False
    return prime_flag                    

def check_if_a_number_is_t_prime(n):
    if n == 4:
        return True
    if n < 4 or n%2==0:
        return False
    sqrt_n = n**0.5
    if sqrt_n==int(sqrt_n):
        if prime_flag[int(sqrt_n)] == True:
            return True
    return False

prime_flag = calculate_prime_flag_for_each_number_upto_limit()
total_numbers = int(input())
input_array = list(map(int,input().split()))
for i in input_array:
    if check_if_a_number_is_t_prime(i)==True:
        print("YES")
    else:
        print("NO")