It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def digit(x):
    digits=[]
    while(x!=0):
        digits.append(x%10)
        x=x//10
    return(digits)
def distinct(x):
    d=digit(x)
    for i in range(len(d)):
        if d.count(d[i])>1:
            return False
    return True
n=int(input())
while True:
    n+=1
    if distinct(n)==True:
        print(n)
        break