It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
# -*- coding: utf-8 -*-
"""
Created on Thu Sep 21 20:36:39 2023

@author: 2300011314
"""

y=int(input())
n=y+1

def judge(year):
    for i in range(10):
        if year.count(str(i))>1:
            return False
    return True 
  
while n>y:
    if judge(str(n))==True:
        break
    n+=1
print(n)