It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def check(a):
    list = []
    while a>0:
        if a%10 in list:
            return False
        list.append(a%10)
        a//=10
    return True

n = int(input())
n+=1
while n<9000:
    if check(n):
        print(n)
        break
    n+=1