It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n = int(input())+1
while n//1000 == ((n//10)%100)//10 or n//1000 == (n//10)%10 or n//1000 == (n%10) or ((n//10)%100)//10 == (n//10)%10 or ((n//10)%100)//10 == (n%10) or (n//10)%10 == n%10:
  n+=1
print(n)