It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def check(n):
    s = str(n)
    l = list(map(int,s))
    d = {i:0 for i in l}
    for i in range(0,4):
        d[l[i]]+=1
    for i in d.values():
        if i>1:
            return False
    return True

n=int(input())
n+=1
while(check(n)==False):
    n+=1
print(n)