It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
def distinct_digits(year):
    digits=set()
    while year>0:
        digit=year%10
        if digit in digits:
            return False
        digits.add(digit)
        year=year//10
    return True
def check_year(y):
    while True:
        y=y+1
        if distinct_digits(y):
            return y
n=int(input())
print(check_year(n))