You've got an undirected graph, consisting of *n* vertices and *m* edges. We will consider the graph's vertices numbered with integers from 1 to *n*. Each vertex of the graph has a color. The color of the *i*-th vertex is an integer *c*<sub class="lower-index">*i*</sub>.

Let's consider all vertices of the graph, that are painted some color *k*. Let's denote a set of such as *V*(*k*). Let's denote the value of the neighbouring color diversity for color *k* as the cardinality of the set *Q*(*k*) = {*c*<sub class="lower-index">*u*</sub> :  *c*<sub class="lower-index">*u*</sub> ≠ *k* and there is vertex *v* belonging to set *V*(*k*) such that nodes *v* and *u* are connected by an edge of the graph}.

Your task is to find such color *k*, which makes the cardinality of set *Q*(*k*) maximum. In other words, you want to find the color that has the most diverse neighbours. Please note, that you want to find such color *k*, that the graph has at least one vertex with such color.
The first line contains two space-separated integers *n*, *m* (1 ≤ *n*, *m* ≤ 10<sup class="upper-index">5</sup>) — the number of vertices end edges of the graph, correspondingly. The second line contains a sequence of integers *c*<sub class="lower-index">1</sub>, *c*<sub class="lower-index">2</sub>, ..., *c*<sub class="lower-index">*n*</sub> (1 ≤ *c*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">5</sup>) — the colors of the graph vertices. The numbers on the line are separated by spaces.

Next *m* lines contain the description of the edges: the *i*-th line contains two space-separated integers *a*<sub class="lower-index">*i*</sub>, *b*<sub class="lower-index">*i*</sub> (1 ≤ *a*<sub class="lower-index">*i*</sub>, *b*<sub class="lower-index">*i*</sub> ≤ *n*; *a*<sub class="lower-index">*i*</sub> ≠ *b*<sub class="lower-index">*i*</sub>) — the numbers of the vertices, connected by the *i*-th edge. 

It is guaranteed that the given graph has no self-loops or multiple edges.
#include <bits/stdc++.h>
using namespace std;
#define int long long // a.k.a. TLE creator
#define all(x) x.begin(), x.end()
template<class A, class B> istream& operator >>(istream &o, pair<A, B> &x){return o >> x.first >> x.second;}
template<class A, class B> ostream& operator <<(ostream &o, pair<A, B> &x){return o << x.first << ' ' << x.second << ' ';}
void setIO(){ios::sync_with_stdio(false); cin.tie(0);}
const int INF = 2e18, MOD = 998244353, N = 1e5 + 2, K = __lg(N) + 1;

int a[N]{}, vis[N]{}, ans = 0, cur = 0;
vector<int> adj[N];

void dfs(int i = 0){
    vis[i] = 1;
    set<int> s;
    for(int j : adj[i]){
        if(!vis[j])dfs(j);
        s.insert(a[j]);
    }
    s.erase(a[i]);
    if(s.size() == cur)ans = min(ans, a[i]);
    if(s.size() > cur){
        ans = a[i];
        cur = s.size();
    }
}

signed main(){
    setIO();
    int n, m;
    cin >> n >> m;
    for(int i = 0; i < n; i++)cin >> a[i];
    for(int i = 0; i < m; i++){
        int u, v;
        cin >> u >> v;
        --u, --v;
        adj[u].push_back(v);
        adj[v].push_back(u);
    }
    dfs();
    cout << ans;
}
