It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n=int(input())
def check(n):
    if help(n+1)==True:
        return n+1
    return check(n+1)
def help(n):
    arr=[0]*10
    for i in str(n):
        arr[int(i)]+=1
    for i in arr:
        if i>1:
            return False
    return True
print(check(n))