It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
y = int(input())

list1 = []
list1.extend(map(int,str(y)))
list2 = []

#print(list1)

list1 = list(set(list1))

#print(list1)

# if len(list1) ==4:
#   print(y)

while len(list1) < 4:
  if len(list1) <4:
    y+=1 
    list1.pop(0)
    list1.append(y)
    list1 = list(set(list1))
  elif len(list1) ==4:
    print(y)
