It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n = int(input())

while True:
    n+=1
    d = {}
    for i in str(n):
        d.update({i:0})

    for i in str(n):
        if i in d:
            d[i]+=1
        else:
            d[i] = 1
    sum = 0
    for i in d:
        if d.get(i) == 1:
            sum+=1

    if sum == 4:
        break
print(n)

      