It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
from collections import Counter
def solve(Y):
    while True:
        Y += 1
        temp = Y
        s = set()
        while temp > 0:
            if temp % 10 in s:
                break
            s.add(temp % 10)
            temp //= 10
            if temp == 0: return Y
    return -1
    
print(solve(int(input())))