It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
year = int(input())

def check_year(v):
    if len(set(list(v))) == len(list(v)):
        return True
    else:
        return False

year += 1
while check_year(str(year)) == False:
    year += 1 

print(year)