It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
from sys import stdin
input = stdin.readline
n=int(input())
a=n+1
def func(num):
    num=str(num)
    set={num[0],num[1],num[2],num[3]}
    return len(set)
while a<9000:
    if func(a)==4:
        print(a)
        break
    else:
        a+=1
        