It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
n=int(input())
L=[]

while True:
    temp=n+1
    
    r=temp%10
    temp=temp//10
    L.append(r)
    r=temp%10
    temp=temp//10
    L.append(r)
    r=temp%10
    temp=temp//10
    L.append(r)
    r=temp%10
    L.append(r)

    
    if L[0]!=L[1] and L[0]!=L[2] and L[0]!=L[3] and L[1]!=L[2] and L[1]!=L[3] and L[2]!=L[3]:

        L.reverse()
        for i in range(4):
            print(L[i])
            
        break

    else:
        L=[]
        n=n+1