It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
year = int(input())
def check(year):
    lst = [int(x) for x in str(year)]
    count = 0
    for i in range (0 , 3):
        for j in range(i+1, 4):
            if list[i] == list[j]:
                count += 1
    if count !=0:
        years += 1
        check(year)
    else:
        print(year)
check(year + 1)
            
        