It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
The single line contains integer *y* (1000 ≤ *y* ≤ 9000) — the year number.
year = int(input())
counter = year + 1

def search(x):
  '''
  Checks if a year number only has distinct digits. Returns True if yes, returns false if no. '''
  temp = list(str(x))
  for i in range(len(temp)-1):
    if temp[i] in temp[i+1:]:
      return False
  return True

def counting(x):
  '''Returns the year that is greater than the input, with only distinct digits'''
  while x <= 9000:
    if search(x):
      return x
    x += 1

print(counting(counter))