Iahub likes trees very much. Recently he discovered an interesting tree named propagating tree. The tree consists of *n* nodes numbered from 1 to *n*, each node *i* having an initial value *a*<sub class="lower-index">*i*</sub>. The root of the tree is node 1.

This tree has a special property: when a value *val* is added to a value of node *i*, the value -*val* is added to values of all the children of node *i*. Note that when you add value -*val* to a child of node *i*, you also add -(-*val*) to all children of the child of node *i* and so on. Look an example explanation to understand better how it works.

This tree supports two types of queries:
 -  "1 *x* *val*" — *val* is added to the value of node *x*; -  "2 *x*" — print the current value of node *x*. 
In order to help Iahub understand the tree better, you must answer *m* queries of the preceding type.
The first line contains two integers *n* and *m* (1 ≤ *n*, *m* ≤ 200000). The second line contains *n* integers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (1 ≤ *a*<sub class="lower-index">*i*</sub> ≤ 1000). Each of the next *n*–1 lines contains two integers *v*<sub class="lower-index">*i*</sub> and *u*<sub class="lower-index">*i*</sub> (1 ≤ *v*<sub class="lower-index">*i*</sub>, *u*<sub class="lower-index">*i*</sub> ≤ *n*), meaning that there is an edge between nodes *v*<sub class="lower-index">*i*</sub> and *u*<sub class="lower-index">*i*</sub>.

Each of the next *m* lines contains a query in the format described above. It is guaranteed that the following constraints hold for all queries: 1 ≤ *x* ≤ *n*, 1 ≤ *val* ≤ 1000.
n,m = map(int,input().split())
values = list(map(int,input().split()))
rebra = []
for i in range(n-1):
    rebra.append(list(map(int,input().split())))
zapr = []
for i in range(m):
    z = list(map(int,input().split()))
    if z[0] == 1:
        v = -z[2]
        values[z[1]-1] -= v
        for j in range(z[1],n-1):
            for e in rebra:
                if e[0] == j: #2
                    values[e[1]-1] += v
            v = -v
    else:
        zapr.append(values[z[1]-1])
for i in zapr:
    print(i)
    
    