Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
n = int(input())
a = [[x for x in input()] for x in range(n)]

for i in range(n):
	for j in range(n):
		if (i>0 and i+1<n and j>0 and j+1<n and
		a[i-1][j] == '#' and a[i][j] == '#' and 
		a[i+1][j] == '#' and a[i][j-1] == '#' and
		a[i][j+1] == '#'):
			a[i-1][j] = a[i][j] = a[i+1][j] = '.'
			a[i][j-1] = a[i][j+1] = '.'

key = True
for i in a:
	if '#' in i:
		key = False
print('YES' if key else 'NO')