The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly.
The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
##str1 = list(str(input()))
##str2 = list(str(input()))
##
#### print(f"This is the first string: {str1}")
##n = len(str2)
##counter = 0
##i = 0
##for i in range(len(str1)):
##    if str1[i] == str2[n-1]:
##        print(str1[i])
##        print(str2[n-1])
##       ## counter += 1
##    i += 1
##
##if counter == n:
##    print("YES")
##
##else:
##    print("NO")



# def translation(str1, str2):
#     n = (len(str1) - 1)
#     counter = 0
#     for i in range(len(str1)):
#         if str1[i] == str2[n-i]:
#             counter += 1
#             # print(str1[i])
#             # print(str2[n-i])
            
#     if counter == len(str1):
#         # return 'NO'
#         print("YES")
        
#     else:
#         # return 'NO'
#         print("NO")

def translation(str1, str2):
    n = (len(str1) - 1)
    counter = 0
    for i in range(len(str1)):
        if str1[i] == str2[n-i]:
            counter += 1
            print(str1[i])
            print(str2[n-i])
                
    if counter == len(str1):
            # return 'NO'
        return "YES"
            
    else:
            # return 'NO'
        return "NO"

        
str1 = list(str(input()))
str2 = list(str(input()))
print(translation(str1, str2))
##n = (len(str1) - 1)
##counter = 0
##for i in range(len(str1)):
##    if str1[i] == str2[n-i]:
##        counter += 1
##        print(str1[i])
##        print(str2[n-i])
##            
##if counter == len(str1):
##        # return 'NO'
##    print("YES")
##        
##else:
##        # return 'NO'
##    print("NO")

# print(translation(str1, str2))
