You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
import random
s = list(map(int, input()))
s.remove(1)
s.remove(6)
s.remove(8)
s.remove(9)
s = sorted(s)
s = " ".join(map(str, s))
p = ["1", "6", "8", "9"]
while True:
    random.shuffle(p)
    k = int("".join(p) + s)
    if k % 7 == 0:
        print(k)
        break
        

		 	 	  	    	  	 				 	    			