Sometimes one has to spell email addresses over the phone. Then one usually pronounces a dot as dot, an at sign as at. As a result, we get something like vasyaatgmaildotcom. Your task is to transform it into a proper email address ([[email protected]](/cdn-cgi/l/email-protection)). 

It is known that a proper email address contains only such symbols as . @ and lower-case Latin letters, doesn't start with and doesn't end with a dot. Also, a proper email address doesn't start with and doesn't end with an at sign. Moreover, an email address contains exactly one such symbol as @, yet may contain any number (possible, zero) of dots. 

You have to carry out a series of replacements so that the length of the result was as short as possible and it was a proper email address. If the lengths are equal, you should print the lexicographically minimal result. 

Overall, two variants of replacement are possible: dot can be replaced by a dot, at can be replaced by an at.
The first line contains the email address description. It is guaranteed that that is a proper email address with all the dots replaced by dot an the at signs replaced by at. The line is not empty and its length does not exceed 100 symbols.

 # ///==========Libraries, Constants and Functions=============///
#mkraghav
import sys

inf = float("inf")
mod = 1000000007


def get_array(): return list(map(int, sys.stdin.readline().split()))


def get_ints(): return map(int, sys.stdin.readline().split())


def input(): return sys.stdin.readline()

def int1():return int(input())

import string

import math


from itertools import combinations
# ///==========MAIN=============///


def main():

    l=(input())
    j2=len(l)

    s=list(l)
    s.pop()
    j=l[len(l)-4:len(l)-1]

    j3=l.index('at')

    if j3==0:

        q4=l[:j3+2]
        q5=l[j3+2:]
        q5=q5.replace('at','@',1)
        l=q4+q5
    else:
        l=l.replace('at','@',1)

    if 'dot' in l:
        i=(l.index('dot'))
    else:
        i=100000

    if (l.count('dot'))>=1 and i!=0:
        l=l.replace('dot','.')


    elif i==0 :
        l4=l[:i+3]
        l5=l[i+3:]
        l5=l5.replace('dot','.')
        l=l4+l5




    if j=='dot':


        l=l[:len(l)-2]+'dot'
    print(l)



















if __name__ == "__main__":
    main()
