Valera has got a rectangle table consisting of *n* rows and *m* columns. Valera numbered the table rows starting from one, from top to bottom and the columns – starting from one, from left to right. We will represent cell that is on the intersection of row *x* and column *y* by a pair of integers (*x*, *y*).

Valera wants to place exactly *k* tubes on his rectangle table. A tube is such sequence of table cells (*x*<sub class="lower-index">1</sub>, *y*<sub class="lower-index">1</sub>), (*x*<sub class="lower-index">2</sub>, *y*<sub class="lower-index">2</sub>), ..., (*x*<sub class="lower-index">*r*</sub>, *y*<sub class="lower-index">*r*</sub>), that: 
 -  *r* ≥ 2; -  for any integer *i* (1 ≤ *i* ≤ *r* - 1) the following equation |*x*<sub class="lower-index">*i*</sub> - *x*<sub class="lower-index">*i* + 1</sub>| + |*y*<sub class="lower-index">*i*</sub> - *y*<sub class="lower-index">*i* + 1</sub>| = 1 holds; -  each table cell, which belongs to the tube, must occur exactly once in the sequence. 
Valera thinks that the tubes are arranged in a fancy manner if the following conditions are fulfilled: 
 -  no pair of tubes has common cells; -  each cell of the table belongs to some tube. 
Help Valera to arrange *k* tubes on his rectangle table in a fancy manner.
The first line contains three space-separated integers *n*, *m*, *k* (2 ≤ *n*, *m* ≤ 300; 2 ≤ 2*k* ≤ *n*·*m*) — the number of rows, the number of columns and the number of tubes, correspondingly.
'''I = lambda: [int(i) for i in input().split()]
import io, os, sys
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline'''

#n = int(input())
#l1 = list(map(int,input().split()))

    
n,m,k = map(int,input().split())
l=[]
c=0
s=0
l1=[]

for i in range(1,n+1):

    if c==0:
        for j in range(1,m+1):
            l+=[i,j]
            c=1

    else:
        for j in range(m,0,-1):
            l+=[i,j]
            c=0
a = n*m-k+1
print(a,*(l[:2*(a)]))
x=a*2
for i in range(k-1):
    print(1,l[x],l[x+1])
    x+=2

    
            
                

            
