You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.

Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resulting number also mustn't contain any leading zeroes.
The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 10<sup class="upper-index">6</sup> characters.
# https://codeforces.com/problemset/problem/375/A

from itertools import permutations

a = list(input().strip())
check=0
for p in permutations(a):
    temp = ''.join(i for i in p)
    if (len(temp) == len(a)):
        if (int(temp) % 7 == 0):
            print(int(temp))
            check=1
            break
if(check==0):
    print(0)
