Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n* × *n* cells. Each cell contains either a symbol '.', or a symbol '#'.

A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.

Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.

Please, tell Ciel if she can draw the crosses in the described way.
The first line contains an integer *n* (3 ≤ *n* ≤ 100) — the size of the board.

Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
def check():
    for i in range(n):
        for j in range(n):
            if board[i][j] == '#':
                return False
    return True

n = int(input())
board = []
for i in range(n):
    board.append([char for char in input()])

for i in range(1,n-1):
    for j in range(1,n-1):
        if board[i][j] == '#' and board[i][j-1] == board[i][j+1] == board[i-1][j] == board[i+1][j] == '#':
            board[i][j] = board[i][j-1] = board[i][j+1] = board[i-1][j] = board[i+1][j] = '@'

print("YES" if check() else "NO")
			 		 	   			 		 	   			   	