Let's assume that we are given a matrix *b* of size *x* × *y*, let's determine the operation of mirroring matrix *b*. The mirroring of matrix *b* is a 2*x* × *y* matrix *c* which has the following properties:
 -  the upper half of matrix *c* (rows with numbers from 1 to *x*) exactly matches *b*; -  the lower half of matrix *c* (rows with numbers from *x* + 1 to 2*x*) is symmetric to the upper one; the symmetry line is the line that separates two halves (the line that goes in the middle, between rows *x* and *x* + 1). 
Sereja has an *n* × *m* matrix *a*. He wants to find such matrix *b*, that it can be transformed into matrix *a*, if we'll perform on it several (possibly zero) mirrorings. What minimum number of rows can such matrix contain?
The first line contains two integers, *n* and *m* (1 ≤ *n*, *m* ≤ 100). Each of the next *n* lines contains *m* integers — the elements of matrix *a*. The *i*-th line contains integers *a*<sub class="lower-index">*i*1</sub>, *a*<sub class="lower-index">*i*2</sub>, ..., *a*<sub class="lower-index">*im*</sub> (0 ≤ *a*<sub class="lower-index">*ij*</sub> ≤ 1) — the *i*-th row of the matrix *a*.
#include <iostream>

using namespace std;

int a[100][100];

int main()
{
    int n, m;
    cin >> n >> m;
    for (int i = 0; i < n; ++i)
        for (int j = 0; j < m; ++j)
            cin >> a[i][j];

    bool b = n % 2 == 0;
    while (b)
    {
        for (int i = 0; i < n / 2; ++i)
        {
            for (int j = 0; j < m; ++j)
            {
                if (a[i][j] != a[n - i - 1][j])
                {
                    b = false;
                    break;
                }
            }
            if (!b) break;
        }
        if (b) n /= 2;
    }

    cout << n << "\n";

    return 0;
}
