You have probably registered on Internet sites many times. And each time you should enter your invented password. Usually the registration form automatically checks the password's crypt resistance. If the user's password isn't complex enough, a message is displayed. Today your task is to implement such an automatic check.

Web-developers of the company Q assume that a password is complex enough, if it meets all of the following conditions:
 -  the password length is at least 5 characters; -  the password contains at least one large English letter; -  the password contains at least one small English letter; -  the password contains at least one digit. 
You are given a password. Please implement the automatic check of its complexity for company Q.
The first line contains a non-empty sequence of characters (at most 100 characters). Each character is either a large English letter, or a small English letter, or a digit, or one of characters: "!", "?", ".", ",", "_".
str = input()
num = ['1','2','3','4','5','6','7','8','9','0']
str_arr = []
char1 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
char2 = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
symbols = ['!','?','.',',','_']
has_num = False
has_char1 = False
has_char2 = False
has_symbols = False
has_len = False


for letter in str:
	str_arr.append(letter)

for i in str_arr:
	if len(str_arr)>=5:
		has_len = True
	if i in num:
		has_num = True
	if i in char1:
		has_char1 = True
	if i in char2:
		has_char2 = True
	if i in symbols:
		has_symbols = True

if has_len and has_num and has_char1 and has_char2 and has_symbols:
	print("Correct")
else:
	print("Too weak")


		
