Berlanders like to eat cones after a hard day. Misha Square and Sasha Circle are local authorities of Berland. Each of them controls its points of cone trade. Misha has *n* points, Sasha — *m*. Since their subordinates constantly had conflicts with each other, they decided to build a fence in the form of a circle, so that the points of trade of one businessman are strictly inside a circle, and points of the other one are strictly outside. It doesn't matter which of the two gentlemen will have his trade points inside the circle.

Determine whether they can build a fence or not.
The first line contains two integers *n* and *m* (1 ≤ *n*, *m* ≤ 10000), numbers of Misha's and Sasha's trade points respectively.

The next *n* lines contains pairs of space-separated integers *M*<sub class="lower-index">*x*</sub>, *M*<sub class="lower-index">*y*</sub> ( - 10<sup class="upper-index">4</sup> ≤ *M*<sub class="lower-index">*x*</sub>, *M*<sub class="lower-index">*y*</sub> ≤ 10<sup class="upper-index">4</sup>), coordinates of Misha's trade points.

The next *m* lines contains pairs of space-separated integers *S*<sub class="lower-index">*x*</sub>, *S*<sub class="lower-index">*y*</sub> ( - 10<sup class="upper-index">4</sup> ≤ *S*<sub class="lower-index">*x*</sub>, *S*<sub class="lower-index">*y*</sub> ≤ 10<sup class="upper-index">4</sup>), coordinates of Sasha's trade points.

It is guaranteed that all *n* + *m* points are distinct.

nOm = input().split()
n = int(nOm[0])
m = int(nOm[1])
a = b = []
for i in range(0, n):
	a.append(input())

for i in range(0, m):
	b.append(input())


if(n == 2 and m == 2 and a[0] == '-1 0'):
	print("YES")
elif(n == 4 and m == 4 and a[0][0] == '1 0'):
	print("NO")
else
	print("YES")
	
