The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them. 

In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2 × 2 square, such that from the four letters of this square you can make word "face". 

You need to write a program that determines the number of faces on the image. The squares that correspond to the faces can overlap.
The first line contains two space-separated integers, *n* and *m* (1 ≤ *n*, *m* ≤ 50) — the height and the width of the image, respectively.

Next *n* lines define the image. Each line contains *m* lowercase Latin letters.
ch= input()
nbr=int(input())
L=""
for i in range(nbr):
  ch0=input()
  L=L+(ch0)

j=0
b=False
ch2=ch[1]+ch[0]
while j<len(L) or b==False:
  if L[i:i+0]==ch or L[i:i+0]==ch2 :
    b=True
  else:
    j=j+1

print(b)