Drazil is playing a math game with Varda.

Let's define <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7020b94c48be2ee5b8eeca05f379c8911bb0e7c4.png" style="max-width: 100.0%;max-height: 100.0%;"/> for positive integer *x* as a product of factorials of its digits. For example, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/6784d861d9a724d0aeddefcb00b7d0c3442ae586.png" style="max-width: 100.0%;max-height: 100.0%;"/>.

First, they choose a decimal number *a* consisting of *n* digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they should find maximum positive number *x* satisfying following two conditions:

1. *x* doesn't contain neither digit 0 nor digit 1.

2. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7020b94c48be2ee5b8eeca05f379c8911bb0e7c4.png" style="max-width: 100.0%;max-height: 100.0%;"/> = <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/aa57e017a6c74d06b0a54bc47e3f6990e5af38c1.png" style="max-width: 100.0%;max-height: 100.0%;"/>.

Help friends find such number.
The first line contains an integer *n* (1 ≤ *n* ≤ 15) — the number of digits in *a*.

The second line contains *n* digits of *a*. There is at least one digit in *a* that is larger than 1. Number *a* may possibly contain leading zeroes.
import sys
input = sys.stdin.readline
from math import prod
from collections import Counter

    #X,Y,Z = list(map(int,input().strip().split()))
def mergeDictionary(dict_1, dict_2):
   dict_3 = {**dict_1, **dict_2}
   for key, value in dict_3.items():
       if key in dict_1 and key in dict_2:
               dict_3[key] = value + dict_1[key]
   return dict_3
   
mod = 998244353
stop_reading_my_code = int(input()) 
for _ in range(stop_reading_my_code):
    #x,y = list(map(int,input().strip().split()))
    #n = int(input().strip())
    arr = input()
    ans = []
    for i in arr:
        if i == "2" :
            ans.append(2)
        elif i == "3":
            ans.append(3)
        elif i == "4":
            ans.extend([2,2,3])
        elif i == "5":
            ans.append(5)
        elif i == "6":
            ans.extend([5,3])
        elif i == "7":
            ans.append(7)
        elif i == "8":
            ans.extend([7,2,2,2])
        elif i == '9':
            ans.extend([7,3,3,2])
        
    ans.sort()
    ans.reverse()
    pr = [str(k) for k in ans]
    print("".join(pr))