Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the contest started and Vasya submitted the problem *d* minutes after the contest started. As you know, on Codeforces the cost of a problem reduces as a round continues. That is, if you submit a problem that costs *p* points *t* minutes after the contest started, you get <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/e7bb7983e9c15baf66651c7643406c249354c8c1.png" style="max-width: 100.0%;max-height: 100.0%;"/> points. 

Misha and Vasya are having an argument trying to find out who got more points. Help them to find out the truth.
The first line contains four integers *a*, *b*, *c*, *d* (250 ≤ *a*, *b* ≤ 3500, 0 ≤ *c*, *d* ≤ 180). 

It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round).
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools

sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]

def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)


def main():
    a,b,c,d = LI()
    t = max(a*3/10, a-a/250*c)
    u = max(b*3/10, b-b/250*d)

    if t == u:
        return 'Tie'
    if t > u:
        return 'Misha'

    return 'Vasya'


print(main())


