The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them. 

In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2 × 2 square, such that from the four letters of this square you can make word "face". 

You need to write a program that determines the number of faces on the image. The squares that correspond to the faces can overlap.
The first line contains two space-separated integers, *n* and *m* (1 ≤ *n*, *m* ≤ 50) — the height and the width of the image, respectively.

Next *n* lines define the image. Each line contains *m* lowercase Latin letters.
n = list(map(int,input().split())) 
face_count = 0
original = []

for i in range(n[0]):
    original.append(input())
lst = original.copy()  
faceind = {"f":[] , "a":[], "c":[], "e":[]}

for i in range(n[0]):
    for j in range(n[1]):
        if str(lst[i][j]) in faceind:
            faceind[str(lst[i][j])].append((i,j))

for i in faceind["f"]:
    temp = tuple(original)
    lst = list(temp)
    r = i[0]
    c = i[1]
    
    if r>0:
        face = "ace"
        try:
            face = face.replace(lst[r-1][c-1], "")
            face = face.replace(lst[r-1][c], "")
            face = face.replace(lst[r][c-1], "")
            if len(face)==0:
                face_count +=1
                lst = list(temp)
        except:
            pass
        face = "ace"      
        try:
            face = face.replace(lst[r-1][c+1], "")
            face = face.replace(lst[r-1][c], "")
            face = face.replace(lst[r][c+1], "")
            if len(face)==0:
                face_count +=1
                lst = list(temp)

        except:
            pass
    
    if r<n[0]:
        face = "ace"
        try:
            face = face.replace(lst[r+1][c-1], "")
            face = face.replace(lst[r+1][c], "")
            face = face.replace(lst[r][c-1], "")
            if len(face)==0:
                face_count +=1
                lst = list(temp)
                
        except:
            pass
                
        face = "ace"      
        try:
            face = face.replace(lst[r+1][c+1], "")
            face = face.replace(lst[r+1][c], "")
            face = face.replace(lst[r][c+1], "")
            if len(face)==0:
                face_count +=1
                lst = list(temp)
                
        except:
            pass
        
print(face_count)    
   
    
    