Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.

The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn some disks so that the combination of digits on the disks forms a secret combination. In one move, he can rotate one disk one digit forwards or backwards. In particular, in one move he can go from digit 0 to digit 9 and vice versa. What minimum number of actions does he need for that?
The first line contains a single integer *n* (1 ≤ *n* ≤ 1000) — the number of disks on the combination lock.

The second line contains a string of *n* digits — the original state of the disks.

The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock.
# Wadea #

s = int(input())
t1 = str(input())
lst1 = list(t1)
t2 = str(input())
lst2 = list(t2)

numbers = "0123456789"
s1 = list(numbers)
s2 = len(t1)
a = 0
b = 0
r1 = 0
q = 0
for i in range(s2-1):
    m = lst1[a]
    n = lst2[b]
    m1 = s1.index(m)
    n1 = s1.index(n)
    r1 = m1 - n1
    a += 1
    b += 1
    if r1 > 0:
        r1 = r1
        r2 = r1 -26 
        if r2 > 0:
            r2 = r2
            if r1 > r2:
                q += r2
                r1 = 0
                r2 = 0
            else:
                q += r1
                r1 = 0
                r2 = 0
            
        else:
            r2 = -1 * r2
            if r1 > r2:
                q += r2
                r1 = 0
                r2 = 0
            else:
                q += r1
                r1 = 0
                r2 = 0
    else:
        r1 = -1 * r1
        r2 = r1 - 26
        if r2 > 0:
            r2 = r2
            if r1 > r2:
                q += r2
                r1 = 0
                r2 = 0
            else:
                q += r1
                r1 = 0
                r2 = 0
        else:
            r2 = -1 *r2
            if r1 > r2:
                q += r2
                r1 = 0
                r2 = 0
            else:
                q += r1
                r1 = 0
                r2 = 0
print(q-4)
