Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
import math as m

n,x = map(int,input().split())
l = []
for i in range (1,x+1):
    if x%i == 0:
        l.append(i)
b = len(l)
ls = l[:]
       
while(ls[b-1]>n):
    ls = ls[1:-1]
    b = b-2
lst = []
for i in range (1,x):
    if i**2 == x:
        l.append(1)
    else:
        l.append(0)
        
if 1 in lst:
        print(int((len(ls)+1)/2))
else:
        print(len(ls))


