Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
from math import sqrt
n,x = map(int,input().split())
cnt = 0
if n==1:
    print([0,1][x==1])
elif x==1:
    print(1)
else:
    sq = int(sqrt(x))+1
    for i in range(2,sq):
        if x%i == 0 and x//i <= n:
            if i == x//i:
                cnt+=1
            else:
                cnt+=2
    if cnt==0 and x<=n:
        cnt=2
    print(cnt)

