Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
import math
n,x = list(map(int,input().split()))
count = 0
if x>n*n:
	print(0)
else:
    i = 1
    while i <= math.sqrt(n):
        if (x%i==0) and (i<=n) and (x//i<=n):
            if i == x//i:
                count=count+1
            else:
                count=count+2
        i = i+1
print(count)