Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
 
#import io, os, sys
#input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
#print = lambda x: sys.stdout.write(str(x) + "\n")
    
II = lambda: int(input())
MII = lambda: map(int, input().split())
LMII = lambda: list(MII())
#SLMII = lambda: sorted(LMII())

n, x = MII()

k = 1
ans = 0
while k*k <= x:
    if not x%k and k <= n and x//k <= n:
        ans += 1 + int(k!=x//k)
    k += 1
    
print(ans)
    