Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
import math
def multiplication_table(a,x):
	sqr_root = int(math.sqrt(x))
	range_factor = min(sqr_root,a)
	count=0
	for i in range(1,range_factor+1):
		if x%i==0:
			if i==x//i:
				count+=1
			elif x//i<=n:
				count+=2
			else:
				pass
	return count
a,x=list(map(int,input().split()))	
print(multiplication_table(a,x))