You are given *n* numbers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>. You can perform at most *k* operations. For each operation you can multiply one of the numbers by *x*. We want to make <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1faa5be276f646dfb07d2a01bf67449ad72c0ef7.png" style="max-width: 100.0%;max-height: 100.0%;"/> as large as possible, where <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ddbf6923ea3f08cb83b08ed026f40a80751dff3f.png" style="max-width: 100.0%;max-height: 100.0%;"/> denotes the bitwise OR. 

Find the maximum possible value of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1faa5be276f646dfb07d2a01bf67449ad72c0ef7.png" style="max-width: 100.0%;max-height: 100.0%;"/> after performing at most *k* operations optimally.
The first line contains three integers *n*, *k* and *x* (1 ≤ *n* ≤ 200 000, 1 ≤ *k* ≤ 10, 2 ≤ *x* ≤ 8).

The second line contains *n* integers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (0 ≤ *a*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>).
def bt(bit,n):
    for i in range(30):
        if (1<<i)&n:
            bit[i]=1
    return bit.copy()
def generate(a):
    bit=[0]*30
    for i in a:
        bit=bt(bit,i)
    return bit
def get_or(a):
    o=0
    for i in a:
        o|=i
    return o
def f(a,k,x):
    bit=[0]*30
    for i in a:
        bit=bt(bit,i)
    goodcnt=[0]*(len(a))
    for val in range(k):
        cmax=0
        cind=0
        for num in range(len(a)):
            a[num]*=x
            tbit=generate(a)
            for i in range(30-1,-1,-1):
                if bit[i]==0 and tbit[i]==1:
                    if i >cmax:
                        cmax=i
                        cind=num
                        break
            a[num]//=x
        a[cind]*=x

    return get_or(a)

n,k,x=map(int,input().strip().split())
a=list(map(int,input().strip().split()))
print(f(a,k,x))