Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string *s* written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful. 

Below there was also written that a string is called beautiful if for each *i* (1 ≤ *i* ≤ |*s*|) there are no more ')' characters than '(' characters among the first *i* characters of *s* and also the total number of '(' characters is equal to the total number of ')' characters. 

Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
The first line of the input contains a string *s* (1 ≤ |*s*| ≤ 10<sup class="upper-index">5</sup>). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that *s* contains at least one '#' character.
arr = input().strip()
last_hash = arr.rindex("#")

parenthesis = 0
result = []
for n, i in enumerate(arr):
    if i == "(": parenthesis += 1
    elif i == ")": parenthesis -= 1
    elif i == "#":
        if n == last_hash:
            result += [f"{parenthesis}"]
            parenthesis = 0
        else:
            result += ["1"] 
            parenthesis -= 1
    # print(i, result, parenthesis)
    if parenthesis < 0:
        break

if parenthesis != 0:
    print("-1")
else:
    print("\n".join(result))
# arr = list(input().strip())
# left_parenthesis, right_parenthesis = arr.count("("), arr.count(")")
# hashtag = arr.count("#")
# total_diff = left_parenthesis - right_parenthesis
# total_diff -= hashtag-1

# if total_diff < 1:
#     print("-1")
# else:
#     parenthesis = 0
#     invalid = 0
#     for i in arr:
#         if i == "(": parenthesis += 1
#         else: parenthesis -= 1
#         if parenthesis < 0:
#             invalid = 1
#             break
#     if invalid: print("-1")
#     else: print("\n".join(["1" for _ in range(hashtag-1)] + [f"{total_diff}"]))
   	  		    		  			  	 	  	   	