The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them. 

In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2 × 2 square, such that from the four letters of this square you can make word "face". 

You need to write a program that determines the number of faces on the image. The squares that correspond to the faces can overlap.
The first line contains two space-separated integers, *n* and *m* (1 ≤ *n*, *m* ≤ 50) — the height and the width of the image, respectively.

Next *n* lines define the image. Each line contains *m* lowercase Latin letters.
from fileinput import *

data = []
for line in input():
    if lineno() == 1:
        [m, n] = list(map(int, line.split()))
    else:
        data.append(line.strip())

if m < 2 or n < 2:
    print(str(0))
else:
    count = 0
    for m_row in range(m-1):
        for n_col in range(n-1):
            s = data[m_row][n_col] + data[m_row][n_col+1] \
                    + data[m_row+1][n_col] + data[m_row+1][n_col+1]
            if set(s) == {'c', 'e', 'f', 'a'}:
                count +=1
    print(str(count))

