Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
siza_table, number = [int(i) for i in input().split()]
i = 1
count = 0
while  i**2 <= number:
    if number%i==0 and i <= siza_table and number//i <= siza_table:
        if i != number//i:
            count +=2
        else:
            count +=1
    i += 1
print(count)