The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them. 

In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2 × 2 square, such that from the four letters of this square you can make word "face". 

You need to write a program that determines the number of faces on the image. The squares that correspond to the faces can overlap.
The first line contains two space-separated integers, *n* and *m* (1 ≤ *n*, *m* ≤ 50) — the height and the width of the image, respectively.

Next *n* lines define the image. Each line contains *m* lowercase Latin letters.
# coding=utf-8


if __name__ == '__main__':
	n, m = str(input()).split()
	n = int(n)
	m = int(m)
	face = list()
	for i in range(n):
		face.append(list(str(input())))
	c = 0
	for i in range(n - 1):
		for j in range(m - 1):
			line = str()
			line += face[i][j]
			line += face[i][j + 1]
			line += face[i + 1][j]
			line += face[i + 1][j + 1]
			if 'f' in line and 'a' in line and 'c' in line and 'e' in line:
				c += 1
	print(c)
