Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
from math import*
n,x=list(map(int,input().split()))
def cal(a,n):
    j=[]
    for i in range(1,int(sqrt(a))+1):
        if a%i==0:
            if i<=n and a/i<=n:
                u=(2,1)[a/i==i]
                j.append(u)
    return j
if x==n**2 or x==1:
    print(1)
else:
    print(sum(cal(x,n)))