Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
def count_cells_with_x(table_size, x):
    count = 0
    i, j = 1, table_size

    while i <= table_size and j >= 1:
        current_value = i * j

        if current_value == x:
            count += 1
            i += 1
            j -= 1
        elif current_value > x:
            j -= 1
        else:
            i += 1

    return count


n, x  = map(int, input().split())
print(count_cells_with_x(n, x))