Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i* × *j*. The rows and columns are numbered starting from 1.

You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
The single line contains numbers *n* and *x* (1 ≤ *n* ≤ 10<sup class="upper-index">5</sup>, 1 ≤ *x* ≤ 10<sup class="upper-index">9</sup>) — the size of the table and the number that we are looking for in the table.
"""
 A. Таблица умножения
"""
from math import sqrt, ceil

n, x = list(map(int, input().split()))

ans = 0
range_object = range(1, min(ceil(sqrt(x)), n + 1))
for i in range_object:
    if x % i == 0:
        if x // i == i:
            ans += 1
        if x // i in range(1, n + 1):
            ans += 2

if n == 1 and x == 1:
    print(1)
else:
    print(ans)
