While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.

He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly *k* messages in his own bag, each was a palindrome string and all those strings had the same length.

He asked you to help him and tell him if he has worn his own back-bag. Check if the given string *s* is a concatenation of *k* palindromes of the same length.
The first line of input contains string *s* containing lowercase English letters (1 ≤ |*s*| ≤ 1000).

The second line contains integer *k* (1 ≤ *k* ≤ 1000).
def is_palin(s):
	return s == s[::-1]

def main():
	s = input()
	k = int(input())
	palin_len = len(s) // k
	start = 0
	end = palin_len
	while end <= len(s):
		#print('start %d end %d' % (start, end))
		if not is_palin(s[start:end]):
			print('NO')
			return
		start = end
		end += palin_len
		k -= 1
	if k == 0:
		print('YES')
	else:
		print('NO')

if __name__ == '__main__':
	main()