You are given *n* numbers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>. You can perform at most *k* operations. For each operation you can multiply one of the numbers by *x*. We want to make <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1faa5be276f646dfb07d2a01bf67449ad72c0ef7.png" style="max-width: 100.0%;max-height: 100.0%;"/> as large as possible, where <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ddbf6923ea3f08cb83b08ed026f40a80751dff3f.png" style="max-width: 100.0%;max-height: 100.0%;"/> denotes the bitwise OR. 

Find the maximum possible value of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1faa5be276f646dfb07d2a01bf67449ad72c0ef7.png" style="max-width: 100.0%;max-height: 100.0%;"/> after performing at most *k* operations optimally.
The first line contains three integers *n*, *k* and *x* (1 ≤ *n* ≤ 200 000, 1 ≤ *k* ≤ 10, 2 ≤ *x* ≤ 8).

The second line contains *n* integers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (0 ≤ *a*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>).
import sys
def get_ints(): return list(map(int, sys.stdin.readline().strip().split()))

def solve(N, K, X, A):
    prefix, suffix = [0] * (N + 2), [0] * (N + 2)
    for i in range(N):
        prefix[i + 1] = prefix[i] | A[i]

    for i in range(N - 1, -1, -1):
        suffix[i] = suffix[i + 1] | A[i]

    ans = 0
    val = X ** K
    for i in range(N):
        ans = max(
            ans,
            prefix[i] | A[i] * val | suffix[i]
        )

    return ans

N, K, X = map(int, input().split())
A = get_ints()
print(solve(N, K, X, A))
