The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them. 

In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2 × 2 square, such that from the four letters of this square you can make word "face". 

You need to write a program that determines the number of faces on the image. The squares that correspond to the faces can overlap.
The first line contains two space-separated integers, *n* and *m* (1 ≤ *n*, *m* ≤ 50) — the height and the width of the image, respectively.

Next *n* lines define the image. Each line contains *m* lowercase Latin letters.
linhas, colunas = [int(item) for item in input().split()]
table = []
for i in range(linhas):
    table.append(list(input()))
faces = 0
for linha in range(linhas-1):
    for coluna in range(colunas-1):
        esquerdaCima = table[linha][coluna]
        direitaCima = table[linha][coluna+1]
        esquerdaBaixo = table[linha+1][coluna]
        direitaBaixo = table[linha+1][coluna+1]
        frase = [esquerdaCima,direitaCima,esquerdaBaixo,direitaBaixo]
        frase.sort()
        if(frase == ['a','c','e','f']):
            faces+=1
print(faces)
 				 	 			  	 	 		 			 	   			