There are two main kinds of events in the life of top-model: fashion shows and photo shoots. Participating in any of these events affects the rating of appropriate top-model. After each photo shoot model's rating increases by *a* and after each fashion show decreases by *b* (designers do too many experiments nowadays). Moreover, sometimes top-models participates in talk shows. After participating in talk show model becomes more popular and increasing of her rating after photo shoots become *c* and decreasing of her rating after fashion show becomes *d*.

Izabella wants to participate in a talk show, but she wants to do it in such a way that her rating will never become negative. Help her to find a suitable moment for participating in the talk show. 

Let's assume that model's career begins in moment 0. At that moment Izabella's rating was equal to *start*. If talk show happens in moment *t* if will affect all events in model's life in interval of time [*t*..*t* + *len*) (including *t* and not including *t* + *len*), where *len* is duration of influence.

Izabella wants to participate in a talk show, but she wants to do it in such a way that her rating will not become become negative before talk show or during period of influence of talk show. Help her to find a suitable moment for participating in the talk show.
In first line there are 7 positive integers *n*, *a*, *b*, *c*, *d*, *start*, *len* (1 ≤ *n* ≤ 3·10<sup class="upper-index">5</sup>, 0 ≤ *start* ≤ 10<sup class="upper-index">9</sup>, 1 ≤ *a*, *b*, *c*, *d*, *len* ≤ 10<sup class="upper-index">9</sup>), where *n* is a number of fashion shows and photo shoots, *a*, *b*, *c* and *d* are rating changes described above, *start* is an initial rating of model and *len* is a duration of influence of talk show.

In next *n* lines descriptions of events are given. Each of those lines contains two integers *t*<sub class="lower-index">*i*</sub> and *q*<sub class="lower-index">*i*</sub> (1 ≤ *t*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>, 0 ≤ *q* ≤ 1) — moment, in which event happens and type of this event. Type 0 corresponds to the fashion show and type 1 — to photo shoot. 

Events are given in order of increasing *t*<sub class="lower-index">*i*</sub>, all *t*<sub class="lower-index">*i*</sub> are different.
none
5 1 1 1 4 0 5
1 1
2 1
3 1
4 0
5 0
6
1 1 2 1 2 1 2
1 0
-1
10 1 1 1 2 0 10
1 1
2 1
3 0
4 0
5 1
6 1
7 1
8 1
9 1
10 1
5
from sys import stdin
from collections import deque
def main():
    n, a, b, c, d, st, l = map(int, input().split())
    q = deque()
    po = q.popleft
    pu = q.append
    mq = deque()
    mpop = mq.pop
    mpo = mq.popleft
    mpu = mq.append
    sb = [0] * (n + 1)
    mst = st
    pu((0, 0, mst, st))
    pp = 0
    for i, line in enumerate(stdin):
        line = line.split()
        t = int(line[0], 10)
        while q and q[0][0] + l <= t:
            p, j, ma, sa = po()
            if ma < 0:
                print -1
                return
            while mq and mq[0][1] < p:
                mpo()
            sa += (-sb[j] + mq[0][0]) if mq else 0
            if ma > sa:
                ma = sa
            if ma >= 0:
                print min(pp, p)
                return
            pp = p + 1
        pu((t, i, mst, st))
        if line[1] == '1':
            st += a
            x = sb[i] + c
        else:
            st -= b
            x = sb[i] - d
        if mst > st:
            mst = st
        while mq and mq[-1][0] > x:
            mpop()
        mpu((x, t))
        sb[i+1] = x
    pu((t + 1, n, mst, st))
    while q:
        p, j, ma, sa = po()
        if ma < 0:
            print -1
            return
        while mq and mq[0][1] < p:
            mpo()
        sa += (-sb[j] + mq[0][0]) if mq else 0
        if ma > sa:
            ma = sa
        if ma >= 0:
            print min(pp, p)
            return
        pp = p + 1
    print (-1)
main()