There are two main kinds of events in the life of top-model: fashion shows and photo shoots. Participating in any of these events affects the rating of appropriate top-model. After each photo shoot model's rating increases by *a* and after each fashion show decreases by *b* (designers do too many experiments nowadays). Moreover, sometimes top-models participates in talk shows. After participating in talk show model becomes more popular and increasing of her rating after photo shoots become *c* and decreasing of her rating after fashion show becomes *d*.

Izabella wants to participate in a talk show, but she wants to do it in such a way that her rating will never become negative. Help her to find a suitable moment for participating in the talk show. 

Let's assume that model's career begins in moment 0. At that moment Izabella's rating was equal to *start*. If talk show happens in moment *t* if will affect all events in model's life in interval of time [*t*..*t* + *len*) (including *t* and not including *t* + *len*), where *len* is duration of influence.

Izabella wants to participate in a talk show, but she wants to do it in such a way that her rating will not become become negative before talk show or during period of influence of talk show. Help her to find a suitable moment for participating in the talk show.
In first line there are 7 positive integers *n*, *a*, *b*, *c*, *d*, *start*, *len* (1 ≤ *n* ≤ 3·10<sup class="upper-index">5</sup>, 0 ≤ *start* ≤ 10<sup class="upper-index">9</sup>, 1 ≤ *a*, *b*, *c*, *d*, *len* ≤ 10<sup class="upper-index">9</sup>), where *n* is a number of fashion shows and photo shoots, *a*, *b*, *c* and *d* are rating changes described above, *start* is an initial rating of model and *len* is a duration of influence of talk show.

In next *n* lines descriptions of events are given. Each of those lines contains two integers *t*<sub class="lower-index">*i*</sub> and *q*<sub class="lower-index">*i*</sub> (1 ≤ *t*<sub class="lower-index">*i*</sub> ≤ 10<sup class="upper-index">9</sup>, 0 ≤ *q* ≤ 1) — moment, in which event happens and type of this event. Type 0 corresponds to the fashion show and type 1 — to photo shoot. 

Events are given in order of increasing *t*<sub class="lower-index">*i*</sub>, all *t*<sub class="lower-index">*i*</sub> are different.
none
5 1 1 1 4 0 5
1 1
2 1
3 1
4 0
5 0
6
1 1 2 1 2 1 2
1 0
-1
10 1 1 1 2 0 10
1 1
2 1
3 0
4 0
5 1
6 1
7 1
8 1
9 1
10 1
5
#include <bits/stdc++.h>

using namespace std;

int main() {
	int n,a,b,c,d,start,len;
	scanf("%d%d%d%d%d%d%d",&n,&a,&b,&c,&d,&start,&len);
	vector <int> t (n), q(n);
	for (int i = 0; i < n; i++) scanf("%d%d",&t[i],&q[i]);
	int j = 0;
	long long df = 0, mn = 0, ac = start;
	vector <int> T;
	T.push_back(-1);
	for (int i = 0; i < n; i++) T.push_back(t[i]);
	for (int i = 0; i < n; i++) {
		while (j < n && t[j]-t[i] < len) {
			df += (q[j] ? c : -d);
			mn = min(mn,df);
			j++;
		}
		if (ac+mn >= 0) {
			cout << T[i]+1 << endl;
			return 0;
		}
		df -= (q[i] ? c : -d);
		mn -= (q[i] ? c : -d);
		ac += (q[i] ? a : -b);

		if (ac < 0) {
			puts("-1");
			return 0;
		}
	}
	cout << T[n]+1 << endl;
}