def max_lt(seq, val):
    """
    Return greatest item in seq for which item < val applies.
    None is returned if seq was empty or all items in seq were >= val.

    >>> max_lt([3, 6, 7, 11], 10)
    7
    >>> max_lt((5, 9, 12, 13), 12)
    9
    """

    idx = len(seq)-1
    while idx >= 0:
        if seq[idx] < val:
            return seq[idx]
        idx -= 1
    return None

    Return greatest item in seq for which item < val applies.
    None is returned if seq was empty or all items in seq were >= val.

    >>> max_lt([3, 6, 7, 11], 10)
    7
    >>> max_lt((5, 9, 12, 13), 12)
    9
    
recipes/Python/415233_Getting_minmax_sequence_greaterless_thsome/recipe-415233.py