def version_compare(v0: str, v1: str) -> int:
    """Returns 1 if version of v0 is larger than v1 and -1 otherwise

    Use this method to compare Python package versions and see which one is
    newer.

    Examples:

        >>> # compare two versions
        >>> version_compare('1.2.0', '1.1.2')
        >>> 1
    """
    v0_parsed = [int(n) for n in v0.split(".")][::-1]
    v1_parsed = [int(n) for n in v1.split(".")][::-1]
    if len(v0_parsed) != 3 or len(v1_parsed) != 3:
        raise ValueError(
            f"Length of version strings is not 3 (expected pattern `x.y.z`) but is "
            f"{v0_parsed} and {v1_parsed}."
        )
    pairs = list(zip(v0_parsed, v1_parsed))[::-1]
    for x, y in pairs:
        if x < y:
            return -1
        if x > y:
            return 1
    return 0
Returns 1 if version of v0 is larger than v1 and -1 otherwise

    Use this method to compare Python package versions and see which one is
    newer.

    Examples:

        >>> # compare two versions
        >>> version_compare('1.2.0', '1.1.2')
        >>> 1
    
lightly/utils/version_compare.py