def containsNearbyAlmostDuplicate(self, nums, k, t):
        """
        :type nums: List[int]
        :type k: int
        :type t: int
        :rtype: bool
        """
        # https://discuss.leetcode.com/topic/19991/o-n-python-using-buckets-with-explanation-10-lines
        # Bucket sort. Each bucket has size of t. For each number, the possible
        # candidate can only be in the same bucket or the two buckets besides.
        # Keep as many as k buckets to ensure that the difference is at most k.
        buckets = {}
        for i, v in enumerate(nums):
            # t == 0 is a special case where we only have to check the bucket
            # that v is in.
            bucketNum, offset = (v / t, 1) if t else (v, 0)
            for idx in xrange(bucketNum - offset, bucketNum + offset + 1):
                if idx in buckets and abs(buckets[idx] - nums[i]) <= t:
                    return True

            buckets[bucketNum] = nums[i]
            if len(buckets) > k:
                # Remove the bucket which is too far away. Beware of zero t.
                del buckets[nums[i - k] / t if t else nums[i - k]]

        return False

        :type nums: List[int]
        :type k: int
        :type t: int
        :rtype: bool
        
python/220_Contains_Duplicate_III.py